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Dafna11 [192]
2 years ago
14

The density of no2 in a 4.50 l tank at 760.0 torr and 25.0 °c is ________ g/l.

Chemistry
2 answers:
kap26 [50]2 years ago
7 0
From  ideal  gas  equation   that   is   PV=nRT
n(number of  moles)=PV/RT
P=760 torr
V=4.50L
R(gas  constant =62.363667torr/l/mol
T=273 +273=298k
n  is   therefore   (760torr x4.50L) /62.36367 torr/L/mol  x298k  =0.184moles
the  molar  mass  of  NO2 is  46  therefore  density=  0.184  x  46=8.464g/l
SCORPION-xisa [38]2 years ago
4 0

Answer:

The nitrogen dioxide gas is 4.43 g/L.

Explanation:

Pressure of the of the gas = P = 760.0 torr = 2.356 atm

(1 torr = 0.00131 atm)

Volume of the tank = 4.50 L

Temperature of the gas = 25 °C = 298 K

Moles of gas = n = \frac{mass}{46 g/mol}

Using an ideal gas equation:

PV=nRT

\frac{P\times 46 g/mol}{RT}=\frac{Mass}{V}=Density

Density=\frac{2.356 atm\times 46 g/mol}{0.0820 L atm/mol K\times 298 K}

Density = 4.43 g/L

The nitrogen dioxide gas is 4.43 g/L.

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A chemist needs to make 250 mL of a 2.50 M aqueous solution of ammonium hydroxide from a 6.00 M ammonium hydroxide solution. How
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Answer:

250 mL (total solution)  = 104 mL (stock solution)  + 146 mL (water)

Explanation:

Data Given

M1 = 6.00 M

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Solution:

As the chemist needs to prepare 250 mL of solution from 6.00 M ammonium hydroxide solution to prepare a 2.50 M aqueous solution of ammonium hydroxide.

Now

first he have to determine the amount of ammonium hydroxide solution that will be taken from6.00 M ammonium hydroxide solution

For this Purpose we use the following formula

                    M1V1=M2V2

Put values from given data in the formula

                   6 x V1 = 2.5 x 250

Rearrange the equation

                   V1 = 2.5 x 250 /6

                    V1 = 104 mL

So 104 mL is the volume of the solution which we have to take from the 6.00 M ammonium hydroxide solution to prepare 2.5 M  aqueous solution of ammonium hydroxide

But we have to prepare 250 mL of the solution.

so the chemist will take 104 mL from 6.00 M ammonium hydroxide solution and have to add 146 mL water to make 250 mL of new solution.

in this question you have to tell about the amount of water that is 146 mL

250 mL (total solution)  = 104 mL (stock solution)  + 146 mL (water)

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Now, let's sum all three together

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