A hole occurs when both numerator and denominator of a rational function have the same factor.
<u>Step-by-step explanation:</u>
While graphing rational function, it has to be converted into the lowest terms by factoring the numerator and denominator. If the numerator and denominator has the same factor, a hole is said to have occurred and to solve the rational function, you have to set the common factor to zero.
After you set it to zero and solve, you obtain the x value which can be then used to find out the value of y.
Is this multiplying or what??? Anyways try calculating those numbers so basically you need to calculate 28x2 or if you have to divide them or multiply them you would get the answer is very simple
Answer:
7.) 7
10.) 0
Step-by-step explanation:
When it means "evaluate the function", it's in essence asking us to see what the function spits out when we feed it a certain input. Our inputs are our x values, which spit out a y value.
Evaluating the function when x = 1:
Let's look at where the function has an x value of 1. We see it near the bottom of the table and see the y value associated with the input is 7. So when the function is fed 1 as an input, it spits out 7.
Evaluating the function when f(x) = - 2:
This one is a weird because of the new notation. Just think of it as some value of f, which we don't know (so we represent it as an x-variable) must equal -2. So let's look at our table to find out where our output is -2. We find that when f(x) = -2 the input is 0. So the input which gives -2 is 0.
The correct answer is B because after you simplifiy the expression, you would get that answer:
7x + 3y - 2 + 6x + 1 + y^2
combine all the like terms to one side first
7x + 6x - 2 + 1 + y^2
then simplify
13x - 1 + y^2 or y^2 + 3y + 13x - 1
Hey there!

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