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Dominik [7]
3 years ago
10

Just look at pic below rn

Mathematics
2 answers:
horrorfan [7]3 years ago
8 0

Answer:

draw an arrow on the 6th line from zero

Step-by-step explanation:

\frac{3}{5} =0.6

no of divisions on scale= \frac{1}{10} = 0.1

so, on the 6th division/line, you need to put an arrow to represent 3/5

sineoko [7]3 years ago
6 0

Answer:

it would be on the 6th tick

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An athlete training for the olympics swims each lap of a four-lap race in the following times: 54.73 , 54.56 , 54.32 , and 54.54
solniwko [45]

Answer:

218.25 seconds

Step-by-step explanation:

54.73

54.56

54.32

54.54

+_____

218.15

3 0
3 years ago
What is 7 to the power of 8 times seven to the power of -4
Elden [556K]
7 to the power of 8 is 5764801 and 7 to the power of -4 is 0.00041649312 so these timed equals

2400.99995<span> </span>
3 0
3 years ago
TV=3x-24 and VX=2x+1. What is the value of VX?<br> 1. 25<br> 2. 99<br> 3. 5<br> 4. 51
Maslowich
ΔTXV is an <span>isosceles triangle because ∡T = ∡X therefore TV = VX.

3x - 24 = 2x + 1    |subtract 2x from both sides

x - 24 = 1    |add 24 to both sides

x = 25
</span>
7 0
2 years ago
Read 2 more answers
The length between the bases on a baseball field is 90 feet. A scale drawing shows the distance between the bases are 2 1/5 inch
kakasveta [241]

Answer:

So the distance from home plate to 2nd base is 127.279 ft

Step-by-step explanation:

I think it is right hope it helps :)

4 0
3 years ago
Read 2 more answers
Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be
Oksana_A [137]
<h2>Hello!</h2>

The answers are:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

<h2>Why?</h2>

To calculate the speed of the cars, we need to write two equations, one for each car, in order to create a relation between the two speeds and be able to calculate one in function of the other.

So,

Tet be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

x_{FirstCar}=x_o+v*t

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

x_{SecondCar}=x_o+(v+14mph)*t

Now, from the statement that both cars met after 2 hours and 45 minutes, and the distance between to cover (between A and B) is 264 miles,  so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph

Then, since we know that they covered a combined distance equal to 264 miles in 2 hours + 45 minutes, we have:

2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours

Writing the equation:

264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph

So, the speed of the first car is equal to 41 mph.

Now, for the second car we have that:

SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph

We have that the speed of the second car is equal to 55 mph.

Hence, the answers are:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

Have a nice day!

7 0
3 years ago
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