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vfiekz [6]
3 years ago
7

The tables represent two linear functions in a system. A 2 column table with 5 rows. The first column, x, has the entries, negat

ive 6, negative 3, 0, 3. The second column, y, has the entries, negative 22, negative 10, 2, 14. A 2 column table with 5 rows. The first column, x, has the entries, negative 6, negative 3, 0, 3. The second column, y, has the entries, negative 30, negative 21, negative 12, negative 3. What is the solution to this system?
Mathematics
1 answer:
jenyasd209 [6]3 years ago
6 0

Answer: (8,-22)

Step-by-step explanation: just took the test

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Answer:

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Simplify x to the 1/3 power MULTIPLIED BY (x to the 1/2 power + 2x to the 2 power )


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x^(1/3) is y such that y^3 = x

(x^(1/3) × x^(1/3) × x^(1/3)) = x^(1/3+1/3+1/3) = x^1 = x


x^(1/2) = √2 = y such that y^2 = x

(2x)^2 = 4x^2






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