500 because in a normal distribution 50% of the total falls below the mean
Answer:
3,432 m²
Step-by-step explanation:
The amount of aluminum in square meters needed to make the mailboxes = 1863(surface area of each mailbox)
Surface area of each mail box = ½(surface area of cylinder) + (Surface area of rectangular prism/box - area of the surface of the box that joins the half-cylinder)
✔️Surface area of ½-cylinder = ½[2πr(h + r)]
r = ½(0.4) = 0.2 m
h = 0.6 m
π = 3.14
Surface area of ½-cylinder = ½[2*3.14*0.2(0.6 + 0.2]
= 0.628(0.8)
Surface area of ½-cylinder = 0.5024 m²
✔️Surface area of the rectangular box/prism = 2(LW + LH + WH)
L = 0.6 m
W = 0.4 m
H = 0.55 m
Surface area = 2(0.6*0.4 + 0.6*0.55 + 0.4*0.55)
Surface area of rectangular box = 1.58 m²
✔️Area of the surface joining the half cylinder and the box = L*W = 0.6*0.4 = 0.24 m²
✅Surface area of 1 mailbox = (0.5024) + (1.58 - 0.24)
= 0.5024 + 1.34
= 1.8424
Amount of aluminum needed to make 1863 mailboxes = 1863 × 1.8424 = 3,432.3912
= 3,432 m²
Answer:
A = 57.97 cm²
Step-by-step explanation:
The area (A) of a trapezium is calculated as
A = 
h (a + b)
where h is the perpendicular height and a, b the parallel bases
Here h = 6.2, a = 10.8 and b = 7.9, thus
A = × 6.2 × (10.8 + 7.9) = 3.1 × 18.7 = 57.97 cm²
Let sum of 3 numbers be x.
Average of 3 numbers and 8 =
25 =
100 = x +8
x= 92.
The sum of 3 numbers is 92.
By pythagorean theorem
a^2+b^2=c^2
We can find that PL is 12.65
and then by altitude theorem
MA*LA=PA^2
we can find the value of MA
12MA=16
MA=1.33
then by the pythagorean theorem
we can use to find PM
MA^2+PA^2=PM^2
so PM=4.22
then to find the are you multiply length by width
PM*PL
12.65*4.22
So the area is 53.38
