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Ber [7]
3 years ago
7

the perimeter of a rectangle is 20 units. The length of the rectangle is the distance from(-2,6) to (5,6) What is the width in u

nits of the rectangles?
Mathematics
1 answer:
DIA [1.3K]3 years ago
4 0

Answer:

3 units.

Step-by-step explanation:

We can calculate the length, since it only moves on the "x" axis, since on the "y" axis, it remains the same.

We know that between -2 to 5, there are 7 units. 2 + 5 = 7.

Therefore this would be the length.

We know that the perimeter is equal to:

p = 2 * w + 2 * l

P = 20

20 = 2 * w + 2 * 7

2 * w = 20 - 14

w = 6/2

w = 3

therefore, the width value is 3 units.

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2/3x - 1/2y = 3
Makovka662 [10]
The correct answer for this question would be the second option. <span>4x - 3y = 18 and x + 2y = 10. So in order to know why this is the answer, let us check it. Since the given numbers have fractions, let us eliminate the fractions.
2/3x - 1/2 y = 3 <<multiply both sides by 6
and we get 4x - 3y = 18 (So this one is correct)
Next,
1/2x + y = 5 << multiply both sides by 2 and we get
x + 2y = 10 (This one is correct too)
Hope this answer helps. </span>
3 0
3 years ago
Read 2 more answers
87th term of 12,0,-12
Elan Coil [88]

Answer:

a_{87} = -1020

Step-by-step explanation:

Given:

The given AP is.

12,0,-12,......

n=87

The first term of an AP a=12

Common difference d=0-12=-12

We use the the formula for nth term of an AP.

a_{n} = a+(n-1)d

for 87th term

a_{87} = 12+(87-1)(-12)

a_{87} = 12+(86)(-12)

a_{87} = 12+(-1032)

a_{87} = 12-1032

a_{87} = -1020

Therefore, The 87th term of given series is -1020.

5 0
3 years ago
There are two different clocks in Wendy's house, one is 20 minutes faster in a day, and the other is 30 minutes slower in a day.
Annette [7]

Answer:

The answer is below

Step-by-step explanation:

For the first clock that is 20 minutes faster in a day, that means it is \frac{20\ min}{60\ min/hr}=\frac{1}{3}hr faster every day. For it to show the correct time, the clock should be 24 hours faster.

Since 1 day = 1/3 hr faster

x days = 24 hr faster

Let x number of days be required to be 24 hr faster. To find x we use the formula:

x=\frac{24 \ hr* 1\ day}{\frac{1}{3}hr }  \\x=72\ days

For the second clock that is 30 minutes slower in a day, that means it is \frac{30\ min}{60\ min/hr}=\frac{1}{2}hr faster every day. For it to show the correct time, the clock should be 24 hours slower.

Since 1 day = 1/2 hr slower

y days = 24 hr faster

Let x number of days be required to be 24 hr slower. To find x we use the formula:

y=\frac{24 \ hr* 1\ day}{\frac{1}{2}hr }  \\y=48\ days

4 0
3 years ago
How to find the least common denominator of 3 fractions?
Lina20 [59]

Answer:

  Find the LCD of the first two, then the LCD of that and the third one.

Step-by-step explanation:

You can do it by finding the LCD of two of the denominators, then the LCD of that and the third denominator.

Or, you can factor each of the denominators and find their LCM by multiplying the unique factors to their highest powers.

___

<u>Example:</u>

  1/21 + 1/35 + 1/45

The LCD of 1/21 and 1/35 is (21·35)/5 = 105. The LCD of 1/105 and 1/45 is ...

  (105·45)/15 = 315

__

Using factoring ...

  • 21 = 3·7
  • 35 = 5·7
  • 45 = 3²·5

LCD = 3²·5·7 = 315

3 0
4 years ago
G=C+ x - y, for x<br> Help me solve this please
dedylja [7]

Answer:

x = g + y - C

Step-by-step explanation:

<u>Step 1:  Add y to both sides</u>

g + y = C+ x - y + y

<em>g + y = C + x</em>

<em />

<u>Step 2:  Subtract C from both sides</u>

g + y - C = C + x - C

<em>g + y - C = x</em>

<em />

Answer:  x = g + y - C

7 0
3 years ago
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