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il63 [147K]
3 years ago
9

Write a sentence to describe how an image is formed on retinawhen looking at distant objects.​

Physics
1 answer:
beks73 [17]3 years ago
7 0

Answer:

An image is formed on the retina with light rays converging most at the cornea and upon entering and exiting the lens. Rays from the top and bottom of the object are traced and produce an inverted real image on the retina. The distance to the object is drawn smaller than scale

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~choices below~
mart [117]
A is the correct answer
5 0
3 years ago
Read 2 more answers
How much potential energy does a 50-N box have when lifted at a height of 1.5M?
nikitadnepr [17]

The correct answer is: Option (A) 75 J

Explanation:

First, be careful with the units here. As you can see it is mentioned that there is a 50N box. It means that the weight (<em>mg</em>) of the box is given as the unit is <em>Newton</em>, not its mass (which is in kg).

As,

Potential-energy = mass * acceleration-due-to-gravity * height

PE = m*g*h --- (A)


In equation (A), mg is actually the weight of the box, which is given.

mg = 50N

h = height = 1.5m

Plug the values in equation (A):

PE = 50 * 1.5  = <em>75 J (Option A)</em>

3 0
3 years ago
1. What do you notice or wonder about ultrasound imaging? (black and white pictures)
a_sh-v [17]

Answer:

the shape how it involve into a picture

Explanation:

3 0
3 years ago
When two capacitors are connected in parallel and then connected to a battery, the total stored energy is 6.9 times greater than
Mumz [18]

Answer:

C1/C2 = 0.213 or C2/C1 = 4.68

Explanation:

Please refer to the attached image for step by step explanation.

5 0
3 years ago
A 0.500-kg stone is moving in a vertical circular path attached to a string that is 75.0 cm long. The stone is moving around the
Semenov [28]

Answer:

B. 7.07 m/s

Explanation:

The velocity of the stone when it leaves the circular path is its tangential velocity, v, which is given by

v=\omega r

where \omega is the angular speed and r is the radius of the circular path.

\omega is given by

\omega = 2\pi f

where f is the frequency of revolution.

Thus

v=2\pi fr

Using values from the question,

v=2\pi\times 1.50\times0.75

<em>Note the conversion of 75 cm to 0.75 m</em>

v=2\times3.14\times 1.50\times0.75 = 9.42\times0.75 = 7.065=7.07

6 0
3 years ago
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