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Dmitriy789 [7]
3 years ago
9

A baby born more than 3 weeks before the due date is considered

Physics
2 answers:
natulia [17]3 years ago
6 0
Fetal because you are still in the womb and not fully developed
klio [65]3 years ago
5 0

Answer:

preterm baby

Explanation:

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Carbon and hydrogen are examples of pure substances or
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The are elements on the periodic table
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The orbits of all the planets in the solar system are slightly elliptical with the exception of _______.
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There is no exception to this. all planets have some eccentricity. it is physically impossible to have an orbit without any eccentricity. However, venus's orbit has the lowest (0.007) eccentricity (closest to circular) so that could be your answer.

Mercury's orbit's eccentricity 0.2

Venus's orbit's eccentricity 0.007 (this is the lowest so it may be your answer)

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Wbob3914

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3 years ago
Why is thermal expansion an important consideration for engineering?
Dennis_Churaev [7]

Answer:

Explanation:

Thermal expansion is where materials expand while being heated, causing them to take up more space. Some materials expand more than others. But this all happens due to the motion of tiny little molecules. Temperature is the average kinetic energy of the molecules in a substance.

Thermal expansion is an important consideration for engineering because different materials exhibit changes in size when exposed to heat. Thus, affecting length, width, surface area, volume, shape etc

8 0
4 years ago
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Two simple pendulums are in two different places. The length of the second pendulum is 0.4 times the length of the first pendulu
faltersainse [42]

Answer:

\sqrt{\frac{4}{9}}

Explanation:

The frequency of a simple pendulum is given by:

f=\frac{1}{2\pi}\sqrt{\frac{g}{L}}

where

g is the acceleration of gravity

L is the length of the pendulum

Calling L_1 the length of the first pendulum and g_1 the acceleration of gravity at the location of the first pendulum, the frequency of the first pendulum is

f_1=\frac{1}{2\pi}\sqrt{\frac{g_1}{L_1}}

The length of the second pendulum is 0.4 times the length of the first pendulum, so

L_2 = 0.4 L_1

while the acceleration of gravity experienced by the second pendulum is 0.9 times the acceleration of gravity experienced by the first pendulum, so

g_2 = 0.9 g_1

So the frequency of the second pendulum is

f_2=\frac{1}{2\pi}\sqrt{\frac{g_2}{L_2}}=\frac{1}{2\pi} \sqrt{\frac{0.9 g_1}{0.4 L_1}}

Therefore the ratio between the two frequencies is

\frac{f_1}{f_2}=\frac{\frac{1}{2\pi}\sqrt{\frac{g_1}{L_1}}}{\frac{1}{2\pi} \sqrt{\frac{0.9 g_1}{0.4 L_1}}}=\sqrt{\frac{0.4}{0.9}}=\sqrt{\frac{4}{9}}

8 0
3 years ago
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