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PolarNik [594]
3 years ago
5

How to draw a drawing graph?

Mathematics
1 answer:
Lapatulllka [165]3 years ago
5 0
Make a horizontal line on the paper. You may draw arrows on the ends of the line to indicate it is a number line that continues past your data sample. Put the label "X" to the right of the line to indicate the x axis. Mark the center of the line with a vertical tick mark and label it 0. This is the origin of the graph. Make equally spaced tick marks on the rest of the x axis. For this example you should label the tick marks from 1 to 10 on the right side of the 0.
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Which expressions are equivalent to the expression −6x + 8? Select all that apply. 1. −2(3x + 4) 2. 2(−3x + 4) 3. 5(x + 1) − 11x
ki77a [65]
1)
-2(3x+4)=-6x-8≠-6x+8

2)
2(-3x+4)=-6x+8

3)
5(x+1)-11x+3=5x+5-11x+3=-6x+8

4)
x+2-7x+6=-6x+8

5)
8-6x=-6x+8

Answer: The expressions 2,3,4 and 5 are equivalents.
6 0
3 years ago
What are the amplitude, period, and phase shift of the given function? f(t)=-1/2sin(3t-2pi)
Romashka [77]

Answer:

The amplitude=|A|=\frac{1}{2}, period=3 and \text{phase shift}=\frac{2\pi}{3}.

Step-by-step explanation:

The given function is

f(t)=-\frac{1}{2}\sin (3t-2\pi)      .... (1)

The general form of sine function is

F(t)=A\sin (Bt-C)+D                 ....(2)

where, |A| is the amplitude, B is period, D is the vertical shift (up or down), and C/B is used to find the phase shift.

On comparing (1) and (2), we get

A=-\frac{1}{2}

B=3

C=2\pi

D=0

So,

amplitude=|A|=\frac{1}{2}

period=3

\text{phase shift}=\frac{2\pi}{3}

Therefore amplitude=|A|=\frac{1}{2}, period=3 and \text{phase shift}=\frac{2\pi}{3}.

8 0
3 years ago
Use an inequality symbol(<>_= to compare _26_54
Rina8888 [55]
26 < 54
26 is less than 54
4 0
3 years ago
Read 2 more answers
Draw a picture of a figure that has more than 3 lines of symmetry. Draw the lines of symmetry
scZoUnD [109]

Answer: A hexagon has 6 lines of symmetry.

5 0
3 years ago
If v lies in the first quadrant and makes an angle π/3 with the positive x-axis and |v| = 8, find v in component form.
e-lub [12.9K]

Answer:

amdlkmflakmflkmasdklmflkansdlkfwelkma;lkdsmlfdsnalkme;klamdlfsndldkanfdlknadlkfn;alkndflkandslknaslfknalkdfnladkfsnlkandslfkn

Step-by-step explanation:

3 0
3 years ago
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