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Maksim231197 [3]
3 years ago
9

PLSSS HELP WILL MARK BRAINLIEST

Physics
1 answer:
alexandr402 [8]3 years ago
3 0
<h2>Hello! </h2>

<h2>Answer:</h2>

<h3>Option 'A' </h3>

<h2>Explanation:</h2>

<h3>They are all the result of high levels of glucose in the bloodstream.</h3>

<h2>Hope it help you </h2>

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The radii of curvature of a biconvex lens are 4 cm and 15 cm. The lens is in air, its index of refraction is 1.5. An object is a
rewona [7]

Answer:

v = 6.315 cm

Explanation:

given,

R₁ = 4 cm = 0.04 m

R₂ = 15 cm = 0.15 m

n =1.5

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}=(n-1)(\dfrac{1}{R_1}-\dfrac{1}{R_2})

\dfrac{1}{v}-\dfrac{1}{-1}=(1.5-1)(\dfrac{1}{0.04}+\dfrac{1}{0.15})

\dfrac{1}{v}+1 = 0.5 \times 31.66

\dfrac{1}{v} = 15.833

v = 0.06315 m

v = 6.315 cm  

hence, the distance of the image from the back surface is v = 6.315 cm

8 0
3 years ago
State three factors that determine the strength of electromagnetic​
Sunny_sXe [5.5K]

Answer:

Factors that affect the strength of electromagnets are the nature of the core material, strength of the current passing through the core, the number of turns of wire on the core and the shape and size of the core.Nov 28, 2020

Explanation:

7 0
3 years ago
Read 2 more answers
The strength of the electric field 0.5 m from a 6 µc charge is n/c. (use k = 8.99 × 109 n•meters squared per coulomb squared and
diamong [38]

53....................................

Explanation:

6 0
2 years ago
A rope pulls a 20 kg box up. If the tension in the rope is 275 N, what is the acceleration of the box?
Nana76 [90]

Answer:

<h3>The answer is 13.75 m/s²</h3>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{275}{20}  =  \frac{55}{4}  \\

We have the final answer as

<h3>13.75 m/s²</h3>

Hope this helps you

4 0
3 years ago
A +26.3 uC charge qy is repelled by a force
Musya8 [376]

Answer:

+1.46×10¯⁶ C

Explanation:

From the question given above, the following data were obtained:

Charge 1 (q₁) = +26.3 μC = +26.3×10¯⁶ C

Force (F) = 0.615 N

Distance apart (r) = 0.750 m

Electrical constant (K) = 9×10⁹ Nm²/C²

Charge 2 (q₂) =?

The value of the second charge can be obtained as follow:

F = Kq₁q₂ / r²

0.615 = 9×10⁹ × 26.3×10¯⁶ × q₂ / 0.750²

0.615 = 236700 × q₂ / 0.5625

Cross multiply

236700 × q₂ = 0.615 × 0.5625

Divide both side by 236700

q₂ = (0.615 × 0.5625) / 236700

q₂ = +1.46×10¯⁶ C

NOTE: The force between them is repulsive as stated from the question. This means that both charge has the same sign. Since the first charge has a positive sign, the second charge also has a positive sign. Thus, the value of the second charge is +1.46×10¯⁶ C

5 0
3 years ago
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