Question

Um automóvel percorre 6,0 km para o norte e, em seguida 8,0 km para o leste. A intensidade do vetor posição, em relação ao ponto de partida é: a) 14 km b) 2,0 km c) 12 km d) 10 km e) 8,0 km

Answer 1

Answer:

Explanation:

A car travels 6.0 km to the north and then 8.0 km to the east. The intensity of the position vector, in relation to the starting point is: a) 14 km b) 2.0 km c) 12 km d) 10 km e) 8.0 km

Check attachment for diagram

The intensity of the position vector is equal to the displacement,

So, to calculate the displacement, we need to find the length of the straight line from starting point to end point.

So, applying Pythagorean theorem

c² = a² + b²

R² = 6² + 36²

R² = 36 + 64

R² = 100

R = √100

R = 10 km.

Verifique el adjunto para ver el diagrama

La intensidad del vector de posición es igual al desplazamiento,

Entonces, para calcular el desplazamiento, necesitamos encontrar la longitud de la línea recta desde el punto inicial hasta el punto final.

Entonces, aplicando el teorema de Pitágoras

c² = a² + b²

R² = 6² + 36²

R² = 36 + 64

R² = 100

R = √100

R = 10 km.