Um automóvel percorre 6,0 km para o norte e, em seguida 8,0 km para o leste. A intensidade do vetor posição, em relação ao ponto
de partida é: a) 14 km b) 2,0 km c) 12 km d) 10 km e) 8,0 km
1 answer:
Answer:
Explanation:
A car travels 6.0 km to the north and then 8.0 km to the east. The intensity of the position vector, in relation to the starting point is: a) 14 km b) 2.0 km c) 12 km d) 10 km e) 8.0 km
Check attachment for diagram
The intensity of the position vector is equal to the displacement,
So, to calculate the displacement, we need to find the length of the straight line from starting point to end point.
So, applying Pythagorean theorem
c² = a² + b²
R² = 6² + 36²
R² = 36 + 64
R² = 100
R = √100
R = 10 km.
Verifique el adjunto para ver el diagrama
La intensidad del vector de posición es igual al desplazamiento,
Entonces, para calcular el desplazamiento, necesitamos encontrar la longitud de la línea recta desde el punto inicial hasta el punto final.
Entonces, aplicando el teorema de Pitágoras
c² = a² + b²
R² = 6² + 36²
R² = 36 + 64
R² = 100
R = √100
R = 10 km.
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Answer:
Explanation:
From the information given:
The motional emf can be computed by using the formula:
E = 0.72 volts
According to the question, suppose the wire segment was parallel, there will no be any emf induced since the magnetic field is present along the y-axis.
As such, for any motional emf should be induced, the magnetic field, length, and velocity are required to be perpendicular to one another .
Then the motional emf will be:
E = 0 (zero)