Answer:
7. 01 * 10^7 N/C
Explanation:
Parameters given:
Distance, y = 2.9 m
Radius, R = 2.9 cm = 0.029m
Charge, Q = 5.0 µC = 5 * 10^(-6) C
Given that:
E = 2πKσ(1- [y/(R² + y²)]) j^
Charge density, σ, is given as:
σ = Q/A = Q/πR²
=> E = 2πKQ/πR² (1- [y/(R² + y²)]) j^
E = 2KQ/R² (1 - [y/(R² + y²)]) j^
E = (2 * 9 * 10^9 * 5 * 10^(-6) / 0.029²) (1 - [2.9/(0.029² + 2.9²)]) j^
E = 107015.46 * 10^3 *(1 - 2.9/8.41) j^
E = 107015.46 * 10^3 * 0.655 j^
E = 7.01 * 10^7 j^ N/C
The magnitude of the electric field is 7.01 * 10^7 N/C. The j^ shows the direction.
Answer:
Dude its just a picture of evaporation taking place in a.....................I don't know.
Explanation:
W^2 = 2 A 8 where A is the angular acceleration.
(3w)^2 = 2 A R where R is the number of revolutions.
Note that you are asked for the additional revolutions.
Answer:
4.56 s
Explanation:
Let t (seconds) be the time it takes from the moment when the motorcycle starts to accelerate until it catches up with the car. Since prior to this they are traveling at constant speed, they would have maintained a distance of 52 m before accelerating.
The distance traveled by the car, with respect the motorcycle position when it start accelerating is
The distance traveled by the motorcycle after accelerating, with respect the motorcycle position when it start accelerating is
When the motorcycle catches up to the car, their position are at the same
