The series is an arithmetic series with first term -10 and common difference (-2-(-10))=8. The general term a_n can be written as
a_n = -10 + 8(n-1)
or
a_n = -18+8n
The last term corresponds to
110 = -18+8n
128 = 8n
16 = n
So, the summation can be written as
X = larger number, y = smaller number
x = y + 12
x + y = 74
y + 12 + y = 74
2y + 12 = 74
2y = 74 - 12
2y = 62
y = 62/2
y = 31
x = y + 12
x = 31 + 12
x = 43
so ur 2 numbers are : 43 and 31
I believe the answer is "true".
Answer:
y=-3x^2+12x+63
Step-by-step explanation:
y=-3(x-7)(x+3)
y=-3(x^2-4x-21)
y=-3x^2+12x+63
Answer:
Take the slopes, such that 7-4/-4+3= 3/-1=-3
So one endpoijt is (-5,10)