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Mumz [18]
3 years ago
7

6th question of the day WHat is the equation for standard equation of circle?

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
4 0

Answer:

Where (h,k) is the center and r is the radius

Step-by-step explanation:

r^2 = (x-h)^2+ (y-k)^2

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ILL MARK U BRILLIANT PLEASE I NEED HELP
ahrayia [7]

Answer:

table, graph or equation

8 0
3 years ago
A function f(x)f(x) is graphed on the coordinate plane.
Effectus [21]

<u>Answer</u>

-4x - 2


<u>Explanation</u>

To get the function needed, first calculate the slope of the graph.

slope = (change in y) / (change in x)

          = (2 - -2)/(-1 - 0)

          = 4/-1

           = -4

Now use one of the point (-1, 2) in the graph and a general point (x,y) to find the function.

-4 = (y - 2)/(x - -1)

-4(x + 1) = y - 2

-4x - 4 = y - 2

y = -4x - 4 + 2

  = -4x - 2


∴ f(x) =  -4x - 2

6 0
3 years ago
Find the original price of a pair of shoes if the sale price is $40 after a %20% discount.
borishaifa [10]
That would be around $200. Because you would take 40 devide by .2 and get 200.
4 0
3 years ago
Solve, be sure to show each step under the original problem for any credit.<br> 1 =k/12 +5
Naya [18.7K]
K = -48

1. subtract 5 from both sides
-4 = k/12

2. multiply 12 from both sides to get k alone
-48 = k


3 0
3 years ago
What proportion of students are willing to report cheating by other students? A project put this question to an SRS of 180 under
krok68 [10]

Answer:

13.89% of students are willing to report cheating by other students.

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 180

Number of students who reported cheating, x = 25

We have to find the proportion of the students are willing to report cheating by other students.

Proportion of students can be calculate as

p = \dfrac{x}{n} = \dfrac{25}{180} = 0.1389\\\\\p = 0.1389\times 100\5\\p = 13.89\%

Thus, 13.89% of students are willing to report cheating by other students.

8 0
3 years ago
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