In circle J with m \angle HJK= 92m∠HJK=92 and HJ=9HJ=9 units find area of sector HJK. Round to the nearest hundredth.
1 answer:
Answer:
65.03square units.
Step-by-step explanation:
Find the diagram in the attachment below.
Area of the sector HJK = theta/360° × πr²
theta is the angle subtended by the sector = ∠HJK = 92°
r is the radius = HJ = 9units.
Substituting the given values in the formula:
Area of sector HJK = 92°/360° × π(9)²
Area of sector HJK = 23,399.28/360
Area of sector HJK = 65.03 square units to nearest hundredth
You might be interested in
Answer:
No
Step-by-step explanation:
By the factor theorem if (x + 2) is a factor of f(x) then f(- 2) = 0
f(- 2)
= 2 +
+ 32(- 2) + 32
= 2(64) - 32 - 64 + 32
= 128 - 32 - 64 + 32
= 64 ≠ 0
Hence (x + 2) is not a factor of f(x)