In circle J with m \angle HJK= 92m∠HJK=92 and HJ=9HJ=9 units find area of sector HJK. Round to the nearest hundredth.
1 answer:
Answer:
65.03square units.
Step-by-step explanation:
Find the diagram in the attachment below.
Area of the sector HJK = theta/360° × πr²
theta is the angle subtended by the sector = ∠HJK = 92°
r is the radius = HJ = 9units.
Substituting the given values in the formula:
Area of sector HJK = 92°/360° × π(9)²
Area of sector HJK = 23,399.28/360
Area of sector HJK = 65.03 square units to nearest hundredth
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Answer:
Step-by-step explanation:
The relevant rule of exponents is ...
(a^b·c^d)^e = a^(be)·c^(de)
Then ...
(m^(5/4)·n^(-4/5))^(7/3) = m^(5/4·7/3)·n^(-4/5·7/3)
= m^(35/12)·n^(-28/15)
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Since you want positive rational exponents, you can write this as ...
= m^(35/12)/n^(28/15)