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3 years ago

In circle J with m \angle HJK= 92m∠HJK=92 and HJ=9HJ=9 units find area of sector HJK. Round to the nearest hundredth.

Mathematics

1 answer:

Diano4ka-milaya [45]3 years ago

6 0

Answer:

65.03square units.

Step-by-step explanation:

Find the diagram in the attachment below.

Area of the sector HJK = theta/360° × πr²

theta is the angle subtended by the sector = ∠HJK = 92°

r is the radius = HJ = 9units.

Substituting the given values in the formula:

Area of sector HJK = 92°/360° × π(9)²

Area of sector HJK = 23,399.28/360

Area of sector HJK = 65.03 square units to nearest hundredth

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Answer:

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Step-by-step explanation:

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Required

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Open bracket

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$m_2 = -\frac{1}{0}$

$m_2 = unde\ fined$

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