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Leokris [45]
3 years ago
11

In circle J with m \angle HJK= 92m∠HJK=92 and HJ=9HJ=9 units find area of sector HJK. Round to the nearest hundredth.

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
6 0

Answer:

65.03square units.

Step-by-step explanation:

Find the diagram in the attachment below.

Area of the sector HJK = theta/360° × πr²

theta is the angle subtended by the sector = ∠HJK = 92°

r is the radius = HJ = 9units.

Substituting the given values in the formula:

Area of sector HJK = 92°/360° × π(9)²

Area of sector HJK = 23,399.28/360

Area of sector HJK = 65.03 square units to nearest hundredth

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Dafna1 [17]

Step 1

<u>Find the slope of the given line</u>

we have

3x+4y=15

Isolate the variable y

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3x+4y-3x=15-3x

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Divide by 4 both sides

y=-\frac{3}{4}x+ \frac{15}{4}

the slope of the given line is

m=-\frac{3}{4}

Step 2

Find the equation of the line that passes through  the point (8,-2) and is parallel to the given line

we know that

if two lines are parallel, then their slopes are equal

The equation of the line into point-slope form is equal to

y-y1=m(x-x1)

we have

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substitute in the equation

y+2=-\frac{3}{4}(x-8)

y=-\frac{3}{4}x+6-2

y=-\frac{3}{4}x+4  or  3x+4y=16

therefore

<u>the answer is</u>

y=-\frac{3}{4}x+4

or

3x+4y=16

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3 years ago
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Answer:

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asambeis [7]
First write what are given from the question
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<span>
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