In circle J with m \angle HJK= 92m∠HJK=92 and HJ=9HJ=9 units find area of sector HJK. Round to the nearest hundredth.
1 answer:
Answer:
65.03square units.
Step-by-step explanation:
Find the diagram in the attachment below.
Area of the sector HJK = theta/360° × πr²
theta is the angle subtended by the sector = ∠HJK = 92°
r is the radius = HJ = 9units.
Substituting the given values in the formula:
Area of sector HJK = 92°/360° × π(9)²
Area of sector HJK = 23,399.28/360
Area of sector HJK = 65.03 square units to nearest hundredth
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Split the shape into smaller shapes, (see attachment)
find the area of the split shapes. So first find the area of the triangles
A = 1/2bh
A = 1/2*2*3
A = 1/2*6
A = 3
so that is the area of one triangle. the area of the other is
A = 1/2*4*3
A = 1/2 * 12
A = 6
now find the area of the rectangle
A = l*w
A = 9*3
A = 27
add them all together
27 + 6+ 3 = 36
the area of the total figure is 36
find the area of the split shapes. So first find the area of the triangles
A = 1/2bh
A = 1/2*2*3
A = 1/2*6
A = 3
so that is the area of one triangle. the area of the other is
A = 1/2*4*3
A = 1/2 * 12
A = 6
now find the area of the rectangle
A = l*w
A = 9*3
A = 27
add them all together
27 + 6+ 3 = 36
the area of the total figure is 36