Answer:
-21 kJ·mol⁻¹
Explanation:
Data:
H₃O⁺ + OH⁻ ⟶ 2H₂O
V/mL: 50 50
c/mol·dm⁻³: 1.0 1.0
ΔT = 4.5 °C
C = 4.184 J·°C⁻¹g⁻¹
C_cal = 50 J·°C⁻¹
Calculations:
(a) Moles of acid
So, we have 0.050 mol of reaction
(b) Volume of solution
V = 50 dm³ + 50 dm³ = 100 dm³
(c) Mass of solution
(d) Calorimetry
There are three energy flows in this reaction.
q₁ = heat from reaction
q₂ = heat to warm the water
q₃ = heat to warm the calorimeter
q₁ + q₂ + q₃ = 0
nΔH + mCΔT + C_calΔT = 0
0.050ΔH + 100×4.184×4.5 + 50×4.5 = 0
0.050ΔH + 1883 + 225 = 0
0.050ΔH + 2108 = 0
0.050ΔH = -2108
ΔH = -2108/0.0500
= -42 000 J/mol
= -42 kJ/mol
This is the heat of reaction for the formation of 2 mol of water
The heat of reaction for the formation of mol of water is -21 kJ·mol⁻¹.
Answer:
The correct answer is - 14.
Explanation:
In the given molecular formula of the aluminum sulphite which is Al2(SO3)3, this molecular formula there different type of elements are bonded together to form this compound each element has a specific number of atoms present. This compound has three elements that are aluminum, sulfur, and oxygen and the atoms are present are:
Al = 2 atoms represented by subscript
S = 3 atoms represented as whole subscripts of sulfite
O = 9 atoms 3 inside bracket and 3 outside of bracket that multiplies.
Thus, total number of atoms are 2+3+9 = 14
Answer:
i am unique and have a specific number in the periodic table
Answer: 66
Explanation: To find the mass number you would have to add the number of protons and the number of neutrons.
