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Gnesinka [82]
4 years ago
13

A calorimeter contains 280.0g of water at 13.5C. When 0.250g of a substance with a molar mass of 510.0g/mol is dissolved, the te

mperature of the resultant solution increases to 17.5C. Assume that the specific heat and density of the resulting solution are equal to those of water, 4.18J/gC and 1.00 g/mL, respectively and assume that no heat is lost to the calorimeter itself, nor to the surroundings. Calculate the amount of heat in Joules released by dissolving the substance.
Chemistry
1 answer:
marin [14]4 years ago
8 0

The change in heat is simply equal to:

change in heat ΔH = final enthalpy – initial enthalpy

ΔH = [280.25 g * 4.18J/gC * (17.5°C)] – [280 g * 4.18J/gC * 13.5°C]

ΔH = 4,699.89 J = 4.7 kJ

 

<span>Hence heat released is about 4.7 kJ</span>

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Answer:

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Explanation:

A hydrocarbon with a <em>double bond</em> in its carbon skeleton is an alkene and has the general form:

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This is, the number of hydrogen atoms is twice the number of carbon atoms.

On the other hand, alkanes have only single bonds, and the compounds with a triple bond in its carbon skeleton are alkynes.

Review each choice:

1) <u>C₃H₈:</u>

  • In this case, the number of hydrogen atoms is 2×3 + 2 = 6 + 2 = 8, which is corresponds to an alkane, not an alkene.

2)<u> C₂H₆</u>

  • For this, the number of hydrogen atoms is 2 × 2 + 2 = 4 + 2 = 6. Again an alkane, not alkene.

3) <u>CH₄</u>

  • Hydrogen atoms: 1 × 2 + 2 = 4 ⇒ an alkane

4) <u>C₂H₄ </u>

  • Hydrogen atoms: 2 × 2  = 4.  This is precisely the relation for an alkene, so this is the hydrocarbon that has a double bond in its carbon skeleton.

  • The chemical formula may be writen as CH₂ = CH₂, to show the double bond.

So, this is the correct answer.

5) <u>C₂H₂</u>

  • Hydrogen atoms: 2 × 2 - 2 = 4 - 2 = 2. This relation of carbon and hydrogen atoms corresponds to a compound with triple bond, i.e an alkyne: CH≡CH.
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Consumers affect the goods and services produced through:

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Answer:

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Explanation:

Hello.

In this case, we can solve this problem by applying the Boyle's law which allows us to understand the pressure-volume behavior as a directly proportional relationship:

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In such away, knowing the both the initial pressure and volume and the final volume, we can compute the final pressure as shown below:

P_2=\frac{P_1V_1}{V_2}

Consider that the given initial pressure is also equal to Pa:

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