Answer:
A gas mixture containing oxygen, nitrogen, and carbon dioxide has a total pressure of 32.5 kPa.
<u>The pressure for oxygen is 3 kPa</u>
Explanation:
According to Dalton's Law of Partial Pressure total exerted by the mixture of non-reacting gases is equal to sum of the partial pressure of each gas.
![P_{total}=P_{1}+P_{2}+P_{3}](https://tex.z-dn.net/?f=P_%7Btotal%7D%3DP_%7B1%7D%2BP_%7B2%7D%2BP_%7B3%7D)
So,
For , a gas mixture containing oxygen, nitrogen, and carbon dioxide has a total pressure:
![P_{total}=P_{O_{2}}+P_{N_{2}}+P_{CO_{2}}](https://tex.z-dn.net/?f=P_%7Btotal%7D%3DP_%7BO_%7B2%7D%7D%2BP_%7BN_%7B2%7D%7D%2BP_%7BCO_%7B2%7D%7D)
![P_{total} = 32.5kPa](https://tex.z-dn.net/?f=P_%7Btotal%7D%20%3D%2032.5kPa)
![P_{O_{2}} = 6.5kPa](https://tex.z-dn.net/?f=P_%7BO_%7B2%7D%7D%20%3D%206.5kPa)
![P_{N_{2}} = 23.0kPa](https://tex.z-dn.net/?f=P_%7BN_%7B2%7D%7D%20%3D%2023.0kPa)
Insert the values in :
![P_{total}=P_{O_{2}}+P_{N_{2}}+P_{CO_{2}}](https://tex.z-dn.net/?f=P_%7Btotal%7D%3DP_%7BO_%7B2%7D%7D%2BP_%7BN_%7B2%7D%7D%2BP_%7BCO_%7B2%7D%7D)
![P_{CO_{2}}= 32.5 - 29.5](https://tex.z-dn.net/?f=P_%7BCO_%7B2%7D%7D%3D%2032.5%20-%2029.5)
![P_{CO_{2}}= 3kPa](https://tex.z-dn.net/?f=P_%7BCO_%7B2%7D%7D%3D%203kPa)
Answer:
1.1
Explanation:
The slope of a line can be calculated using the values of the x and y corrdinates. The equation is given as;
M = ΔY / ΔX = Y2 - Y1 / X2 - X1
From the points;
(25.6cm³ , 28.16g) - (X1, Y1)
(17.3cm³, 19.03g) - (X2, Y2)
Inserting the values into the equation;
M = 19.03 - 28.16 / 17.3 - 25.6
M = -9.13 / -8.3 = 1.1
Evaporation and transpiration
A. We can calculate the initial concentrations of each by
the formula:
initial concentration ci = initial volume * initial
concentration / total mixture volume
where,
total mixture volume = 10 mL + 20 mL + 10 mL + 10 mL = 50
mL
ci (acetone) = 10 mL * 4.0 M / 50 mL = 0.8 M
ci (H+) = 20 mL * 1.0 M / 50 mL = 0.4 M (note: there is only 1 H+ per
1 HCl)
ci (I2) = 10 mL * 0.0050 M / 50 mL = 0.001 M
B. The rate of reaction is determined to be complete when
all of I2 is consumed. This is signified by complete disappearance of I2 color
in the solution. The rate therefore is:
rate of reaction = 0.001 M / 120 seconds
rate of reaction = 8.33 x 10^-6 M / s
Answer:
Blooms are alluring and show up in various hues and shapes to draw in pollinators who help in dust move. Most blooms have four primary parts: sepals, petals, stamens, and carpels. The stamens are the male part though the carpels are the female piece of the blossom.
Sepal: The outer parts of the flower (often green and leaf-like) that enclose a developing bud.
Petal: The parts of a flower that are often conspicuously colored.
Stamen: The pollen producing part of a flower, usually with a slender filament supporting the anther.
Anther: The part of the stamen where pollen is produced.
Pistil: The ovule producing part of a flower. The ovary often supports a long style, topped by a stigma. The mature ovary is a fruit, and the mature ovule is a seed.
Stigma: The part of the pistil where pollen germinates.
Ovary: The enlarged basal portion of the pistil where ovules are produced.
Receptacle: The part of a flower stalk where the parts of the flower are attached