Answer:
The specific heat of the metal is 0,50 J/gºC
Explanation:
Assume that no heat is lost to the surroundings
(Q = m . C . ΔT)metal + (Q = m . C . ΔT)water = 0
Let's replace our values.
55g . C . (18,7ºC - 75ºC) + 100g . 4,184 J/g·°C . (18,7ºC - 15ºC) = 0
55g . C . -56,3 ºC + 418,4J/·°C . 3,7ºC = 0
-3096,5 gºC . C + 1548,08 J = 0
1548,08 J = 3096,5 gºC . C
1548,08 J / 3096,5 gºC = C = 0,50 J/gºC
