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max2010maxim [7]
3 years ago
15

PLZZZZZZZZZZZZZZ HELP!!!!!!

Mathematics
1 answer:
exis [7]3 years ago
8 0

Answer:

1. 9.4

2. 4.1

Step-by-step explanation:

9.375 rounds to 9.4

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The function f is defined by f(x) = 3x - 4cos(2x + 1), and its derivative is f'(x) = 3 + 8sin(2x + 1). What are all values of th
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Answer:

f ( x )  does not satisfy the mean value theorem

Step-by-step explanation:

The given data :-

  • f(x) = 3x - 4 cos ( 2x + 1 )
  • f'(x) = 3 +8 sin ( 2x + 1 )
  • The interval [ -1 , 2 ]

Solution :-

i) f(x) is continuous on [ -1 , 2 ]

ii) f(x) is derivable on ( -1 , 2 )

f ( -1 ) = 3 * (-1 ) - 4 cos [ 2 * ( -1 )  + 1 ]  = - 3 + cos (-1 ) = - 3 - 4 * 0.9998 = - 6.992

f ( 2 ) = 3 * 2 - 4 cos ( 4 * 2 + 1 ) = 6 + 4 cos 9  = 6 - 3.9507 = - 3.04924

iii) f ( -1 ) ≠ f ( 2 )

f ( x ) is not real valued function so it does not satisfy the mean value theorem

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3 years ago
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denis23 [38]
It would take 1hr because if you subtract the hrs
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Write an explicit formula for each sequence.<br> 3, 7, 11, 15, ...
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Step-by-step explanation:

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Step-by-step explanation:

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