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ASHA 777 [7]
3 years ago
11

CAN SOMEONE PLS HELP!!!

Mathematics
1 answer:
Soloha48 [4]3 years ago
8 0
Where’s the question
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How do I find the area of a circle when the circumference is 58 pie
aksik [14]
C=2\pir
A=\pir<span>²

C=2</span>\pir=58\pi
2r=58
r=29

A=\pir<span>²
A=29</span><span>²</span>\pi
A=841\pi
8 0
3 years ago
Read 2 more answers
1. Rich wants to buy a coat priced at x dollars. It is on sale for 20% off. He must
alexandr1967 [171]

Answer: x-0.20x+0.0725x

Step-by-step explanation:

Let x be the price. 20% (0.20) 7.25% (0.0725)

x-0.20x+0.0725x

6 0
3 years ago
HELP ME ASAP!!!!!!!
olga nikolaevna [1]

Answer:

3hours and 30 minutes moving and 2 and a half hours stationary

Step-by-step explanation:

1 hour + 30 minutes + 1 hour + 30 minutes + 30 minutes for moving

1 hour + 1 hour + 30 minutes for stationary.

3 0
3 years ago
Pleaseee help!
user100 [1]

Step-by-step explanation:

f(3)=?

f(x)=2x+5

put x=3,

f(3)=2(3)+5=6+5=11

------------

g(2)=?

g(x)=x^2-3

put x=2,

g(2)=2^2-3=4-3=1

-----------------

g(f(-1))=?

g(x)=x^2-3

and f(-1)=2(-1)+5= -2+5=3

so g(f(-1))=3^2-3=9-3=6

----------------

f(g(-1))=?

f(x)=2x+5

g(x)=g(-1)=(-1)^2-3=1-3= -2

f(g(-1))=2(-2)+5= -4+5=1

----------------

g(f(x))=?

g(x)= x^2-3

put x=f(x),

g(f(x))=f(x)^2-3=(2x+5)^2-3=4x+25+20x-3=24x+25

7 0
3 years ago
Use the parabola tool to graph the quadratic function f(x)=(x-5)^2+1
andrey2020 [161]

Answer:

Look to the attached graph

Step-by-step explanation:

* Lets revise how to graph the quadratic function

- Find the vertex of it

- Find the y-intercept

- Find the x-intercept

∵ f(x) = (x - 5)² + 1 ⇒ the completing square form

- The completing square form for any quadratic is

 ( x - h)² + k, where h and k are the coordinate of the vertex point

* Lets compare the two forms

∵ (x - h)² + k = (x - 5)² + 1

∴ h = 5 and k = 1

∴ The vertex of the parabola is (5 , 1)

- To find the x-intercept put f(x) = 0

∵ (x - 5)² + 1 = 0 ⇒ subtract 1 from both sides

∴ (x - 5)² = -1 ⇒ the square can not give -ve number

∴ The parabola does not intersect the x-axis

- To find the y-intercept put x = 0

∵ f(0) = (0 - 5)² + 1 = 25 + 1 = 26

∴ The parabola intersects the y-axis at point (0 , 26)

- The parabola is opened upward because the coefficient of x² is +ve

* Now lets graph it

- Look to the attached graph

5 0
3 years ago
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