You subtract the ones place, then the tens, and lastly the hundreds place. Your answer will be 184 if you are looking for the answer as well.
Differentiating an integral removes the integral.
f(x) = integral of dt/sqrt(t^3 + 2)
f'(x) = 1/sqrt(x^3 + 2)
f'(1) = 1/sqrt(1^3 + 2)
f'(1) = 1/sqrt(3) = sqrt(3)/3.
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Answer:
x = 4y + 28
Step-by-step explanation:
x/4 - 7 = y
+7 +7
x/4 = y + 7
× 4 × 4
x = 4y + 28
Given :
On the first day of ticket sales the school sold 10 senior tickets and 1 child ticket for a total of $85 .
The school took in $75 on the second day by selling 5 senior citizens tickets and 7 child tickets.
To Find :
The price of a senior ticket and the price of a child ticket.
Solution :
Let, price of senior ticket and child ticket is x and y respectively.
Mathematical equation of condition 1 :
10x + y = 85 ...1)
Mathematical equation of condition 2 :
5x + 7y = 75 ...2)
Solving equation 1 and 2, we get :
2(2) - (1) :
2( 5x + 7y - 75 ) - ( 10x +y - 85 ) = 0
10x + 14y - 150 - 10x - y + 85 = 0
13y = 65
y = 5
10x - 5 = 85
x = 8
Therefore, price of a senior ticket and the price of a child ticket $8 and $5.
Hence, this is the required solution.
Answer: none of those, 276...?
Step-by-step explanation:
You need to know the least common denominator (LCD) of 12 and 23 if you want to add or subtract two fractions with 12 and 23 as denominators.
The least common denominator, also called lowest common denominator (LCD), of 12 and 23 is 276.
Here is a math problem example where you need to know the LCD of 12 and 23 to solve:
3/12 + 2/23 = ?
Step 1) Take the LCD and divide each denominator by it as follows:
276/12 = 23
276/23 = 12
Step 2) Multiply each nominator with the respective answers from Step 1:
3 x 23 = 69
2 x 12 = 24
Step 3) Put it all together to solve the problem:
69/276 + 24/276 = 93/276
= 3/12 + 2/23 = 93/276
It's that easy! Once again, the lowest common denominator (LCD) of 12 and 23 is as follows:
276
