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Burka [1]
3 years ago
9

Does pure water conducts electricity?why?​

Chemistry
2 answers:
USPshnik [31]3 years ago
5 0

Answer:

no

Explanation:

pure water does not conduct electricity. Any impurities, like salts, in the water enable it to conduct electricity.

NISA [10]3 years ago
5 0

Answer: No, pure water does NOT conduct electricity.

Explanation:

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Molarity, is the concentration of a solution expressed in terms of moles solute per liter of solution. What is the molarity of a
pishuonlain [190]

molarity of the CuSO₄ solution = 0.68 moles/L

Explanation:

The formula for molar concentration is:

molar concentration (molarity) = number of moles / solution volume (L)

number of moles = mass / molecular weight

number of moles of CuSO₄ = 12.304 / 159.6

number of moles of CuSO₄ = 0.07709 moles

molar concentration of the CuSO₄ solution = 0.07709 / 0.1127

molar concentration of the CuSO₄ solution = 0.68 moles/L

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3 years ago
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4 years ago
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Ozone, o3, is a product in automobile exhaust by the reaction represented by the equation no2(g) + o2(g) --> 3no(g) + o3(g).
svetoff [14.1K]

Answer: 2.1 g mass of ozone(O_{3}) is predicted to form from the reaction of 2.0 g NO_{2} in a car's exhaust and excess oxygen

Given information : Mass of NO_{2} = 2.0 g and O_{2} is in excess.

We need to calculate the mass of ozone (O_{3})

Mass of ozone(O_{3}) is calculated with the help of mass of NO_{2} using stoichiometry.

NO_{2} + O_{2}\rightarrow NO + O_{3}

Step 1 : Convert grams of NO_{2} to moles of NO_{2}.

Moles = \frac{Grams}{Molar mass}

Molar mass of NO_{2} = 46.0 g/mol

Moles = \frac{2.0g}{46.0\frac{g}{mol}}

Moles of NO_{2} = 0.043 mol

Step 2 : Find the moles of O_{3} using moles of NO_{2}.

Moles of O_{3} is calculated by using moles of NO_{2} with the help of mole ratio.

A mole ratio is ​the ratio between the amounts in moles of any two compounds involved in a chemical reaction. The mole ratio may be determined by examining the coefficients in front of formulas in a balanced chemical equation.

From the balanced chemical equation we can see that coefficient of NO_{2} is 1 and coefficient of O3 is 1 , so mole ratio of O_{3} to NO_{2} is 1:1

Moles of O_{3} = (0.043 mol NO_{2})\times \frac{(1 mol O_{3})}{(1 mol NO_{2})}

Moles of O_{3} = (0.043)\times \frac{(1 mol O_{3})}{(1)}

Moles of O_{3} = 0.043 mol

Step 3 : Convert moles of O_{3} to grams of O_{3}

Grams = Moles X Molar mass

Molar mass of O_{3} = 48.0 g/mol

Grams = (0.043 mol O_{3})\times (\frac{48 g O_{3}}{1 mol O_{3}})

Grams = (0.043)\times (\frac{48 g O_{3}}{1})

Grams = 2.1 g O_{3}

Note : The above three steps can also be done using a single step setup.

Grams of O_{3} = (2.0 gNO_{2})\times \frac{(1mol NO_{2})}{(46.0 g NO_{2})}\times \frac{(1 mol O_{3})}{(1 mol NO_{2})}\times \frac{(48.0 g O_{3})}{(1 mol O_{3})}

Grams of O_{3} = (2.0 )\times \frac{(1)}{(46.0 )}\times \frac{(1)}{(1)}\times \frac{(48.0 g O_{3})}{(1)}

Grams of O_{3} = 2.1 grams


4 0
3 years ago
How many moles are 2.54×10^29 molecules of H20?​
Mademuasel [1]

Answer:

421,787 moles.

Explanation:

No. of Molecules of H20=2.54×10²⁹

1 mole=6.022×10²³=Avagadro No.

No. of moles=Given no. of moles/Avagadro No.

=(2.54×10²⁹)/(6.022×10²³)=421,786.782=421,787(approx)

4 0
3 years ago
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