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kipiarov [429]
3 years ago
10

Describe two variables that affect the rate of diffusion

Chemistry
1 answer:
Katyanochek1 [597]3 years ago
5 0

Answer:

The two variables affecting the rate of diffusion are the concentration gradient and size of the molecule. Concentration gradient: The movement of the substance is generally along the concentration gradient of the solute and it moves from a region of its higher concentration to a region of its lower concentration.

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Decreased, this is due to the roots of the plants holding the soil together
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Glucose, c6h12o6, is used as an energy source by the human body. the overall reaction in the body is described by the equation
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What energy is using the telephone?
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A 0.175 M solution of an enantiomerically pure chiral compound D has an observed rotation of +0.27° in a 1-dm sample
-BARSIC- [3]

Answer:

The specific rotation of D is 11.60° mL/g dm

Explanation:

Given that:

The path length (l) =  1 dm

Observed rotation (∝) = + 0.27°

Molarity = 0.175 M

Molar mass = 133.0 g/mol

Concentration in (g/mL) = 0.175 mol/L × 133.0 g/mol

Concentration in (g/mL) = 23.275 g/L

Since 1 L = 1000 mL

Concentration in (g/mL) = 0.023275 g/mL

The specific rotation [∝] = ∝/(1×c)

= 0.27°/( 1  dm ×  0.023275 g/mL )

= 11.60° mL/g dm

Thus, the specific rotation of D is 11.60° mL/g dm

3 0
3 years ago
How many mL of 0.013 M potassium hydroxide are required to reach the equivalence point in the titration of 75 mL 0.166 M hydrocy
umka21 [38]

Answer:

957.7mL

Explanation:

Using the formula below;

CaVa = CbVb

Where;

Ca = concentration of acid (M)

Va = volume of acid (mL)

Cb = concentration of base (M)

Vb = volume of base (mL)

According to the information provided in this question:

Ca = 0.166 M

Cb = 0.013 M

Va = 75mL

Vb = ?

Using CaVa = CbVb

0.166 × 75 = 0.013 × Vb

12.45 = 0.013Vb

Vb =12.45/0.013

Vb = 957.7mL

6 0
2 years ago
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