Answer:
35.42g
Explanation:
LiOH + KCI → LiCl + KOH
Let us determine the molar mass of LiOH and LiCl. This is illustrated below:
Molar Mass of LiOH = 7 + 16 + 1 = 24g/mol
Molar Mass of LiCl = 7 + 35.5 = 42.5g/mol.
Now, we can obtain the theoretical yield of LiCl as follow:
From the equation above,
24g of LiOH reacted to produce 42.5g of LiCl.
Therefore, 20g of LiOH will react to produce = (20 x 42.5)/24 = 35.42g of LiCl.
From the above calculations, the theoretical yield of LiCl is 35.42g
To determine the total number of moles that are in the hormone, you would simply convert that to grams and then use the molar mass if the formula to solve for the total number of moles in the compound.
Which atom?
Atomic mass - proton
The balanced chemical reaction is expressed as:
<span>4hcl(g)+o2(g)→2h2o(l)+2cl2(g)
To determine the percent yield of the reaction, we need to calculate for the theoretical yield. This is the maximum amount of the product that can be produced from the reaction given the initial amounts of the reactants. First, we identify the limiting reactant as follows:
</span><span>63.1 g of hcl ( 1 mol / 36.46 g ) ( 1 mol O2 / 4 mol HCl) ( 32 g / mol) = 13.85 g O2
17.2 g of o2 ( 1 mol / 32 g ) ( 4 mol HCl / 1 mol O2) ( 36.46 g / mol) = 78.39 g HCl
Therefore, the limiting reactant would be HCl. We use the value for the HCl to calculate for the theoretical yield.
</span>63.1 g of hcl ( 1 mol / 36.46 g ) ( 2 mol Cl2 / 4 mol HCl) ( 70.9 g / mol ) = 61.35 g Cl2
Percent yield = actual / theoretical x 100
= 59.6 / 61.35 x 100
= 97.1%
