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vekshin1
3 years ago
13

How can I separate gasoline and vegetable oil?

Chemistry
1 answer:
leonid [27]3 years ago
3 0

Answer: WAter

Explanation:

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Picture has the question
xenn [34]

Answer:I believe it is 5

Explanation:

8 0
3 years ago
Read 2 more answers
Wskaż substancję, która ma największą zawartość procentową węgla w cząsteczce:
MrRa [10]

Answer: C2H4

Explanation:

The percentage composition of ethanol ( C2H5OH ) consist of 52.2% Carbon, Hydrogen of 13.0 and 34.8% of Oxygen.

The percentage composition of ethane gas (C2H6) consist of 80.0% carbon and 20.0% hydrogen.

The composition of Ethylene Glycols i.e C2H4(OH)2 is Carbon of 39.7%, 9.7% hydrogen and 51.6% oxygen.

The percent composition of c2h4 is 86% carbon, and 14% hydrogen.

From the information given, the substance with the highest percentage of carbon is C2H4

7 0
3 years ago
Consider the molecules: scl2, f2, cs2, cf4, and brcl. select the choice where the bonds of the molecules are arranged in order o
elena-s [515]

The polarity of a bond depends on the difference in electronegativities of the atoms involved in bonding. Greater this difference, greater is the polarity

1) In SCl2 we have the S-Cl bond

Electronegativity values: S = 2.5, Cl = 3

Difference = 3.0 -2.5 = 0.5

2) In F2 we have the F-F bond

Electronegativity value: F = 4.0

Difference = 4.0-4.0 = 0

3) In CS2 we have the C-S bond

Electronegativity value: C = 2.5, S = 2.5

Difference = 2.5 -2.5 = 0

4) In CF4 we have the C-F bond

Electronegativity values: C = 2.5, F = 4.0

Difference = 4.0 -2.5 = 1.5

5) In BrCl we have the Br-Cl bond

Electronegativity values: Br = 2.8, Cl = 3

Difference = 3.0 -2.8 = 0.2

Therefore, the increasing order of polarity is

F2 = CS2 < BrCl < SCl2 < CF4

5 0
3 years ago
What part of the atom is represented by the letter Z?
pashok25 [27]

Answer:

The proton of the atom

4 0
2 years ago
A urine sample has a mass of 147 g and a density of 1.020 g/mL. What is the volume of this sample?
son4ous [18]

So we know that the equation for density is:

D=\frac{m}{V}

where D is the density, m is the mass in grams, and V is the volume in mL.

So since we know two of the variables, mass and density, we can solve for the volume:

\frac{1.020g}{mL}=\frac{147g}{V}

V=\frac{147g}{\frac{1.020g}{mL}}

V=144.12mL

Therefore, the volume of this urine sample is 144.12mL.

5 0
3 years ago
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