The question is incomplete,the complete question :
Calculate the molality of a 10.0% (by mass) aqueous solution of hydrochloric acid:
a) 0.274 m
b) 2.74 m
c) 3.05 m
d) 4.33 m
e) the density of the solution is needed to solve the problem
Answer:
The molality of a 10.0% (by mass) aqueous solution of hydrochloric acid is 3.05 mol/kg.
Explanation:
10.0% (by mass) aqueous solution of hydrochloric acid.
10 grams of HCl is present in 100 g of solution.
Mass of HCl = 10 g
Mass of solution = 100 g
Mass of solution = Mass of solute + Mass of water
Mass of water = 100 g - 10 g = 90 g
Moles of HCl = 
Mass of water in kilograms = 0.090 kg
Molality = 
The molality of a 10.0% (by mass) aqueous solution of hydrochloric acid is 3.05 mol/kg.
Answer:
E. (None of these).
It is 0.333 M.
Explanation:
A molar solution would contain 183 g in 1 liter.
By proportion, this solution contains 18.3 * 1000/300
= 61 g per liter.
So it is 61 / 183 = 0.333 M.
Answer:
CaCl2, Li2S, AlCl3, AlCl3, K2S
Explanation:
When figuring out which is a better conductor of electricity you want to look at which has the largest yield of dissociated ions.
U can show him that Earth isn't getting smaller, because things WOULD be getting smaller, and our houses would be getting smaller, IF everything shrunk WITH Earth.
Answer:
Molar mass of unknown solute is 679 g/mol
Explanation:
Let us assume that the solute is a non-electrolyte.
For a solution with non-electrolyte solute remains dissolved in it -
Depression in freezing point of solution, 
where, m is molality of solute in solution and 
is cryogenoscopic constant of solvent.
Here 
If molar mass of unknown solute is M g/mol then-
So, 
so, M = 679 g/mol
