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Romashka-Z-Leto [24]
2 years ago
6

Howtocalculatethevolumeofcarbondioxideproducedwhen400gofmarblewereats.t.p​

Chemistry
1 answer:
lys-0071 [83]2 years ago
3 0

Answer:

so 0.15 moles X 22.4 dm3/mole=3.36 dm3. Next we find the moles of hexane combusted, and then the moles of CO2. Finally, we find the volume of CO2 using the fact that at STP, 1 mole of gas = 22.4 dm3.

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Calculate the number of Cl atoms that are in 1.1 x 10^-21 moles of Cl atoms.
Margarita [4]

According to Avogadro's number there are 62.53 atoms of chlorine in 1.1x 10^-21 moles of Cl atoms.

<h3>What is Avogadro's number?</h3>

Avogadro's number is defined as a proportionality factor which relates number of constituent particles with the amount of substance which is present in the sample.

According to the definitions, Avogadro's number depend on determined value of mass of one atom of those elements.It bridges the gap between macroscopic and microscopic world by relating amount of substance with number of particles.

Number of atoms can be calculated using Avogadro's number as follows: mass/molar mass×Avogadro's number or number of moles×Avogadro's number.

ON substitution in above formula number of atoms=1.1×10²¹×6.023×10²³=62.53 atoms

Thus, there are 62.53 chlorine  atoms in 1.1x 10^-21 moles of Cl atoms.

Learn more about Avogadro's number,here:

brainly.com/question/11907018

#SPJ1

6 0
1 year ago
Which of the following is NOT one of the three main global climate zones?
krok68 [10]
The answer is Latitude (B)
8 0
2 years ago
The Ksp of yttrium iodate, Y(IO3)3 , is 1.12×10−10 . Calculate the molar solubility, s , of this compound.
torisob [31]

Answer:

1.427x10^-3mol per L

Explanation:

Y(IO_{3} )_{3} ---- Y^{3+} +IO_{3} ^{3-}

I could use ⇌ in the math editor so I used ----

from the question each mole of Y(IO3)3 is dissolved  and this is giving us a mole of Y3+ and a mole of IO3^3-

Ksp = [Y^3+][IO3-]^3

So that,

1.12x10^-10 = [S][3S]^3

such that

1.12x10^-10 = 27S^4

the value of s is 0.001427mol per L

= 1.427x10^-3mol per L

so in conclusion

the molar solubility is therefore 1.427x10^-3mol per L

3 0
3 years ago
Compared to the nonmetals in Period 2, the metals in Period 2 generally have larger
konstantin123 [22]
The answer is atomic radii; the size or radii of an atom increases from left to right, versus the ionization energies and electronegativities of atoms which increase from right to left.
6 0
3 years ago
I need help with a questino
kipiarov [429]

Explanation:

What will the question be ?

6 0
2 years ago
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