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Natasha2012 [34]
3 years ago
13

What are these labels?

Chemistry
1 answer:
trasher [3.6K]3 years ago
4 0

Answer:

From left to right

Neutral

Acid

Base

Explanation:

So using HSAB theory hard and soft (Lewis) acids and bases.

OH - Is a Hard Base

H+ Strong Acid

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_____ properties are involved when ice melts to form water and that water boils to form steam
tatyana61 [14]

Answer:

Physical properties are involved when ice melts to form water and that water boils to form steam

Explanation:

This is because there in no chemical reaction taking place, just a physical change.

A physical change in a change in which the chemical structure of the substance does not change. Ice, water and steam are all the same on a molecular level, thus changing from ice to water or from water to steam are physical changes.

6 0
3 years ago
How many liters in 4.4 grams of CO2 at STP?
d1i1m1o1n [39]

Answer:

2.24 Liters are in 4.4 grams of CO2 at STP

5 0
4 years ago
Solution of the Schrodinger Wave Equation for the hydrogen atom results in a set of functions (orbitals) that describe the behav
kenny6666 [7]

Answer:

n is the principal quantum number, it specifies the energy and average distance from the nucleus

l is the orbital quantum number, it specifies the subshell/orbital shape

ml is the magnetic quantum number and specifies the orbital orientation

Explanation:

The Schrödinger wave equation is solved for the hydrogen atom to yield three sets of quantum numbers.

The principal quantum number corresponds to the energy level in the Bohr model and also shows the average distance of the electron from the nucleus.

The orbital quantum number reveals the subshell where an electron is found as well as the shape of the orbital. E.g p-orbitals are dumbbell shaped.

The magnetic quantum number shows the orientation of an orbital in space. Its values range from -l to +l

7 0
3 years ago
Homeostasis subheading<br> The maintenance of stable internal conditions is called
melamori03 [73]

Answer:

<h3>homeostasis</h3>

•the maintenance of a stable internal environment

<u><em>Hope </em><em>this</em><em> helps</em><em> </em><em>:</em><em>)</em></u>

6 0
3 years ago
A sample of helium gas has a volume of 1.50 L at 159 K and 5.00 atm. When the gas is compressed to 0.200 L at 50.0 atm, the temp
Brums [2.3K]

Answer:

ghdtgfgrdvreeeegrwwggegteefewqrwefrwerrftrtdsfgyuytfgererdf

Explanation:

The given data is as follows.

     V_{1} = 1.50 L,    T_{1} = 159 K,

      P_{1} = 5.00 atm,   V_{2} = 0.2 L,

       T_{2} = ?,       P_{2} = 50.0 atm  

And, according to ideal gas equation,  

               \frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}

Hence, putting the given values into the above formula to calculate the value of final temperature as follows.          

 \frac{5.0 atm \times 1.50 L}{159 K} = \frac{5 atm \times 0.2 L}{T_{2}}

            T_{2} = 21.27 K

Thus, we can conclude that the final temperature is 21.27 K .

5 0
3 years ago
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