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Sphinxa [80]
3 years ago
9

How many liters in 4.4 grams of CO2 at STP?

Chemistry
1 answer:
d1i1m1o1n [39]3 years ago
5 0

Answer:

2.24 Liters are in 4.4 grams of CO2 at STP

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When 125 mL of 0.150 M Pb(NO3)2 is mixed with 145 mL of 0.200 M KBr, 4.92 g of PbBr2 is collected. Calculate the percent yield.
Semenov [28]

Answer:

Y = 92.5 %

Explanation:

Hello there!

In this case, since the reaction between lead (II) nitrate and potassium bromide is:

Pb(NO_3)_2+2KBr\rightarrow PbBr_2+2KNO_3

Exhibits a 1:2 mole ratio of the former to the later, we can calculate the moles of lead (II) bromide product to figure out the limiting reactant:

0.125L*0.150\frac{molPb(NO_3)_2}{L} *\frac{1molPbBr_2}{1molPb(NO_3)_2} =0.01875molPbBr_2\\\\0.145L*0.200\frac{molKBr}{L} *\frac{1molPbBr_2}{2molKBr} =0.0145molPbBr_2

Thus, the limiting reactant is the KBr as it yields the fewest moles of PbBr2 product. Afterwards, we calculate the mass of product by using its molar mass:

0.0145molPbBr_2*\frac{367.01gPbBr_2}{1molPbBr_2} =5.32gPbBr_2

And the resulting percent yield:

Y=\frac{4.92g}{5.32g} *100\%\\\\Y=92.5\%

Regards!

4 0
3 years ago
Whats is causing the ice block to melt
slavikrds [6]

Answer:

see explanation

Explanation:

Ice usually has tightly packed molecules at a low temperature. When it comes in contact with a higher temperature or room temperature, the ice molecules gain energy and the molecular tension increases which causes the state to change to liquid. Therefore, a <u>high temperature</u> causes an ice block to melt.

5 0
3 years ago
A 5-kg quantity of radioactive isotope decays to 2 kg after 10 years. Find the decay constant of the isotope.k = _____
Dvinal [7]

Answer:

k = -0.09165 years^(-1)

Explanation:

The exponential decay model of a radioactive isotope is generally given as;

A(t) = A_o(e^(kt))

Where;

A_o is quantity of isotope before decay, k is decay constant and A(t) is quantity after t years

We are given;

A_o = 5 kg

A(10) = 2kg

t = 10 years

Thus;

A(10) = 2 = 5(e^(10k))

Thus;

2 = 5(e^(10k))

2/5 = (e^(10k))

0.4 = (e^(10k))

In 0.4 = 10k

-0.9164 = 10k

k = -0.9164/10

k = -0.09165 years^(-1)

7 0
2 years ago
PlEASE HELP! 40!
podryga [215]

Answer:

moles Na = 0.1114 g / 22.9898 g/mol=0.004846

moles Tc = 0.4562g /98.9063 g/mol=0.004612

mass O = 0.8961 - ( 0.1114 + 0.4562)=03285 g

moles O = 0.3285 g/ 15.999 g/mol=0.02053

divide by the smallest

0.02053/ 0.004612 =4.45 => O

0.004846/ 0.004612 = 1.0 => Tc

to get whole numbers multiply by 2

Na2Tc2O 9

Explanation:

Hope it right hope it helps

5 0
2 years ago
The specific heat of a certain type of metal is 0.128 J / (g ⋅ ∘ C). What is the final temperature if 305 J of heat is added to
Arte-miy333 [17]

Answer:

Final T° is 45.5°C

Explanation:

Formula for calorimetry is:

Q = m . C .  ΔT , where

ΔT = Final T° - Initial T°

C = Specific heat

m = mass

Let's replace with the data given

305 J = 93.4 g . 0.128 J/g°C . (Final T° - 20°C)

305 J / 93.4 g . 0.128 J/g°C  = Final T° - 20°C

25.5°C = Final T° - 20°C → Final T° = 25.5°C + 20°C = 45.5°C

7 0
3 years ago
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