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melamori03 [73]
3 years ago
14

Abeline is creating a box design for a company. The front, back, and sides will be painted, but the top and bottom will not be p

ainted. A prism has a length of 10 feet, height of 8 feet, and width of 12 feet. Which net could be used to find the surface area of the sides that will be painted? A net has 3 rectangles in a row side by side. Another 3 rectangles connect to the middle rectangle side by side. The top 3 rectangles and the middle bottom rectangle are shaded. A net has 3 rectangles in a row side by side. Another 3 rectangles connect to the middle rectangle side by side. The first and third rectangle of the top 3 rectangles are shaded. A net has 3 rectangles in a row side by side. Another 3 rectangles connect to the middle rectangle side by side. The first and third rectangle of the top 3 rectangles are shaded, and the first and third rectangle of the bottom 3 rectangles are shaded. A net has 3 rectangles in a row side by side. Another 3 rectangles connect to the middle rectangle side by side. The middle 4 rectangles are shaded.
Mathematics
1 answer:
just olya [345]3 years ago
4 0

Answer:

it is the first one

Step-by-step explanation:

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Use the equation a = IaIâ
german

Answer:

a) \:\:=\sqrt{14}\cdot \frac{\:\:}{\sqrt{14} }

b)\:\:=\sqrt{29} \cdot \frac{\:\:}{\sqrt{29} }

c) \:\:=7\cdot \frac{\:\:}{7}

Step-by-step explanation:

a) Let <u>a</u>=<2,1,-3>

The magnitude of <u>a</u> is |a|=\sqrt{2^2+1^2+(-3)^2}

|a|=\sqrt{4+1+9}=\sqrt{14}

The unit vector in the direction of a is

\hat{a}=\frac{\:\:}{\sqrt{14} }

Using the relation a=|a|\hat{a}, we have

\:\:=\sqrt{14}\cdot \frac{\:\:}{\sqrt{14} }

b) Let a=2i - 3j + 4k

|a|=\sqrt{2^2+(-3)^2+4^2}

|a|=\sqrt{4+9+16}=\sqrt{29}

\hat{a}=\frac{\:\:}{\sqrt{29} }

Using the relation a=|a|\hat{a}, we have

\:\:=\sqrt{29} \cdot \frac{\:\:}{\sqrt{29} }

c) Let us first find the sum of <1, 2, -3> and <2, 4, 1> to get:

<1+2, 2+4, -3+1>=<3, 6, -2>

Let a=<3, 6, -2>

The magnitude is

|a|=\sqrt{3^2+6^2+(-2)^2}

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The unit vector in the direction of <u>a</u> is

\hat{a}=\frac{\:\:}{7}

Using the relation a=|a|\hat{a}, we have

\:\:=7\cdot \frac{\:\:}{7}

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Answer:

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Step-by-step explanation:

Once you start graphing for this equation you will see that -5,4 is one of the points.

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