Determine whether the following procedure is a binomial experiment.

A graph is constructed such that time (in seconds) is the X-variable and distance (in miles) is the Y-variable. If you plot the

boyakko [2]

5/1 or 5 as slope is the rise or y, over the run or x

3 0

2 years ago

Whats 2099 dived by 800

sergejj [24]

Answer:

2099/800= 2.62375

Step-by-step explanation:

5 0

2 years ago

Help<br><br> Determine which equation is parallel to line jk and which is perpendicular to line jk.

alukav5142 [94]

Answer:

5x + 3y = 13 parallel.

6x - 10y = 7 perpendicular.

Step-by-step explanation:

Two lines with slopes $m_1$ and $m_2$ are parallel when $m_1=m_2$ and are perpendicular when $m_1*m_2=-1$

Now determine the slope of all the lines

The line jk passes through the points

(-5,5) and (1,-5) so its slope is

$\frac{-5-5}{1-(-5)}=\frac{-10}{6}=-\frac{5}{3}$

To determine the slope of the lines in the blue rectangles, isolate y from each one and the coefficient of x is the slope

5x-3y = 8 ------> y = (5/3)x + 8/3 ------> slope 5/3

Neither parallel nor perpendicular.

6x+10y = 11 ------> y = (-6/10)x + 11/10 = (-3/5)x + 11/10 ------> slope -3/5

Neither parallel nor perpendicular.

5x + 3y = 13 ------> y = (-5/3)x + 13/3 ------> slope -5/3

This line is parallel

6x - 10y = 7 ------> y = (6/10)x - 7/10 = (3/5)x -7/10 ------> slope 3/5

Since (-5/3)(3/5) = -1 this line is perpendicular.

8 0

2 years ago

WILL MARK BRAINLIEST Imagine that you are plotting points on a coordinate plane. Each axis is labeled with integers from -5 to 5

Fudgin [204]

Answer:

The coordinate of a point is its location on a grid.

The point will be located halfway between -2 and -3 on the x-axis, on -4 on the y-axis

The coordinate is given as:

Express as decimals

The above point means that:

This means that:

The point will be located halfway between -2 and -3 on the x-axis, on -4 on the y-axis

Step-by-step explanation:

7 0

1 year ago

If the growth rate of bacteria at any time t is proportional to the number present at t and triples in 1 week

serg [7]

The population after 20 weeks will be 403.42 $x_{0}$ in which $x_{0}$ is the initial population.

Given that the growth rate of bacteria at any time t is proportional to the number present at t and triples in 1 week.

We are required to find the number of bacteria present after 10 weeks.

let the number of bacteria present at t is x.

So,

dx/dt∝x

dx/dt=kx

1/x dx=k dt

Now integrate both sides.

$\int\limits {1/x} \, dx$ = $\int\limits{k} \, dt$

log x=kt+log c----------1

Put t=0

log $x_{0}$ =0 +log c ( $x_{0}$ shows the population in beginning)

Cancelling log from both sides.

c= $x_{0}$

So put c= $x_{0}$ in 1

log x=kt+log $x_{0}$

log x=log $e^{kt}$ +log $x_{0}$

log x=log $e^{kt}x_{0}$

x= $e^{kt}x_{0}$

We have been given that the population triples in a week so we have to put the value of x=2 $x_{0}$ and t=1 to get the value of k.

2 $x_{0}$ = $e^{k} x_{0}$

2= $e^{k}$

log 2=k

We have to now put the value of t=20 and k=log 2 ,to get the population after 20 weeks.

x= $e^{20log 2}$ $x_{0}$

x= $e^{0.30*2}$ $x_{0}$

x= $e^{6}x_{0}$

x=403.42 $x_{0}$

Hence the population after 20 weeks will be 403.42 $x_{0}$ in which $x_{0}$ is the initial population.

Learn more about growth rate at brainly.com/question/25849702

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The given question is incomplete as the question incudes the following:

Calculate the population after 20 weeks.

5 0

1 year ago