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Nataly_w [17]
3 years ago
12

Which condition is necessary for water droplets to condense and form clouds?

Physics
2 answers:
-Dominant- [34]3 years ago
5 0

Answer:

ice crystals in air

Explanation:

Mists structure when the undetectable water fume noticeable all around gathers into obvious water beads or ice gems. For this to occur, the bundle of air must be immersed, for example unfit to hold all the water it contains in fume structure, so it begins to consolidate into a fluid or strong structure.(hopes this helps)

Artyom0805 [142]3 years ago
4 0

Answer:

A

Explanation:

THIS IS THE CORRECT ONE I JUST DID EDG 2020 TRUST ME

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A 3.1-kilogram gun initially at rest is free to
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The conservation of momentum states that the total momentum in a system is constant if there is no external force acting on the system. The total momentum in the gun bullet system is 0 so it must stay that way.

The momentum of the bullet is mv = 0.015*500=7.5
The momentum of the gun must be the same to keep the total momentum of the system equal to zero, so we know that p = 7.5 for the gun.
Substituting this in we get:

7.5=3.1x
x=7.5/3.1
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A child has an ear canal that is 1.3 cm long. Assume the speed of sound is v = 344 m/s.
kap26 [50]

Answer:

The  frequencies are (f, f_1) =  (6615.4 \ Hz , 19846.2\ Hz)

Explanation:

From the question we are told that

  The  length of the ear canal is  l = 1.3 \ cm  =\frac{1.3}{100}  =  0.013 \ m

   The  speed of sound is assumed to be  v_s  =  344 \ m/s

Now  taking look at a typical  ear canal  we see that we assume it is  a  closed pipe

   Now the fundamental harmonics for the pipe(ear canal) is mathematically represented as

            f = \frac{v_s}{4 * l }

 substituting values  

          f = \frac{344}{4 * 0.013 }

         f = 6615.4 \ Hz

Also the the second harmonic for the pipe (ear canal) is mathematically represented as

        f_1 =  \frac{3v_s}{4 * l}

 substituting values  

       f_1 =  \frac{3 *  344}{4 * 0.013}

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Given that sound would be loudest in the pipe at the frequency, it implies that the child  will have an increased audible sensitivity at this  frequencies

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