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user100 [1]
1 year ago
9

A student holding a 324Hz tuning fork approaches a wall at a speed of 6ms^(-1). The speed of sound in air is 336ms^(-1). What fr

equency will the student detect from waves omitted from the fork and waves coming from the wall?​
Physics
1 answer:
Mashutka [201]1 year ago
8 0

The frequency the student detect from waves omitted from the fork and waves coming from the wall is 348.1 Hz.

<h3>Frequency detected by the student</h3>

The observed frequency is determined by applying Doppler effect;

f' = f₀(v + v₀)/(v)

where;

  • f' is the observed frequency
  • v is speed of sound
  • v₀ is the source speed
  • f₀ is the original frequency

f' = 342(6 + 336)/(336)

f' = 348.1 Hz

Thus, the frequency the student detect from waves omitted from the fork and waves coming from the wall is 348.1 Hz.

Learn more about observed frequency here: brainly.com/question/10728818

#SPJ1

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P_{sol}=50.4\ mm.Hg

Explanation:

According to given:

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  • molecular mass of water, M_w=2+16=18\ g.mol^{-1}
  • ∵Density of water is 0.992\ g.cm^{-3}= 0.992\ g.mL^{-1}
  • ∴mass of water in 316 mL, m_w=316\times 0.992=313.5 g
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<em>Upon the formation of solution the vapour pressure will be reduced since we have one component of solution as non-volatile.</em>

<u>moles of water in the given quantity:</u>

n_w=\frac{m_w}{M_w}

n_w=\frac{313.5}{18}

n_w=17.42 moles

<u>moles of glycerin in the given quantity:</u>

n_g=\frac{m_g}{M_g}

n_g=\frac{154}{92}

n_g=1.674 moles

<u>Now the mole fraction of water:</u>

X_w=\frac{n_w}{n_w+n_g}

X_w=\frac{17.42}{17.42+1.674}

X_w=0.912

<em>Since glycerin is non-volatile in nature so the vapor pressure of the resulting solution will be due to water only.</em>

\therefore P_{sol}=X_w\times P_x

\therefore P_{sol}=0.912\times 55.32

P_{sol}=50.4\ mm.Hg

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