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Phoenix [80]
3 years ago
13

In a hydraulic system, a 100.-newton force is applied to a small piston with an area of 0.0020 m2 . What pressure, in pascals, w

ill be transmitted in the hydraulic system?
Physics
2 answers:
masha68 [24]3 years ago
7 0
The pressure is the force divided by the area to which the force is applied, so in this problem it is equal to:
p= \frac{F}{A}= \frac{100 N}{0.0020 m^2}=5 \cdot 10^4 Pa
Annette [7]3 years ago
4 0

Answer:

5 × 10^4 Pa

Explanation:

pressure is defined as a measure of force exerted on a surface per unit square. the formula for pressure is force per unit area

Pressure= \frac{Force}{area}

P=\frac{F}{A}

F=100N

A=0.0020m²

∴P=\frac{100}{0.0020}

P=5×10⁴N/m²

1N/m² = 1Pa

∴5×10⁴N/m² = 5×10⁴Pa

pressure in pascals transmitted in the hydraulic system -5×10⁴Pa

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a) The charge on the outer surface is 1.2\cdot 10^{-12} C

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Explanation:

a)

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d=1.4\cdot 10^{-8} m is the distance between the two plates

Substituting,

C=\frac{(4.3)(8.85\cdot 10^{-12})(5.1\cdot 10^{-9})}{1.4\cdot 10^{-8}}=1.4\cdot 10^{-11} F

The capacity of the membrane is related to the potential difference between the two surfaces by

C=\frac{Q}{\Delta V}

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Solving for Q, we find

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b)

We said that the net charge on the outer surface is

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N=\frac{Q}{e}=\frac{1.2\cdot 10^{-12}}{1.6\cdot 10^{-19}}=7.5\cdot 10^6

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