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3 years ago

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In a hydraulic system, a 100.-newton force is applied to a small piston with an area of 0.0020 m2 . What pressure, in pascals, w

ill be transmitted in the hydraulic system?

2 answers:

masha68 [24]3 years ago

7 0

The pressure is the force divided by the area to which the force is applied, so in this problem it is equal to:
$p= \frac{F}{A}= \frac{100 N}{0.0020 m^2}=5 \cdot 10^4 Pa$

Annette [7]3 years ago

4 0

Answer:

5 × 10^4 Pa

Explanation:

pressure is defined as a measure of force exerted on a surface per unit square. the formula for pressure is force per unit area

Pressure= $\frac{Force}{area}$

P= $\frac{F}{A}$

F=100N

A=0.0020m²

∴P= $\frac{100}{0.0020}$

P=5×10⁴N/m²

1N/m² = 1Pa

∴5×10⁴N/m² = 5×10⁴Pa

pressure in pascals transmitted in the hydraulic system -5×10⁴Pa

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By equating equation (1) and (2) we have:

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Since $v_{f_{2}}^{2}$ = 0 at the maximum height (h):

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Hence, the time when they pass each other is:

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Then, when they are passing the height is the same for both = 3h/4.

I hope it helps you!

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