Answer:
Velocity of Object with 2 kg= 3.390 m/s
Velocity of Object with 3 kg= 3.404 m/s
Explanation:
From the picture, it can be seen that object B is initially at rest while object A is travelling at a speed of 5m/s. After the collision, Object A moves at an angle of 65 degrees while object B moves at an angle of 37 degrees.
We also know that momentum of a closed system is conserved.
Initial momentum along the x-axis = 2*5.5 = 11
Initial momentum along y-axis = 0
Final momentum along x-axis= a*Cos(65)*2 +b*Cos(37) *3= 11 (a is the velocity of object A of 2 kg after collision where as b is the velocity of object B of 3 kg after collision. velocity is multiplied by cosines of the angle from x axis to give the horizontal component of the velocities).
Final momentum along y-axis = a*Sin(65)*2 - b*Sin(37)*3 =0 (We can see that vertical components of velocity are opposite in direction to each other)
Solve both the equations simultaneously for a and b.
Explanation:
1N=9,81 kg
1. 9,81×500×10=<u>49.050</u>
2. 9,81×100×40=39.240
option 1 does more wor
For the rest 3 km
Bholu need to run in 5 minutes so
He need to 3 × 1000 / 5 × 60 m/s
3000/ 300 = 10 m/s
So , his speed should be 1 m/s to reach in 5 minute
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Where power<span> P is in watts, voltage V is in volts and current I is in amperes (DC).</span>Power Formula<span> 2 – Mechanical </span>power equation<span>: </span>Power<span> P = E ⁄ t where </span>power<span> P is in watts, </span>Power<span> P = work / time (W ⁄ t). Energy E is in joules, and time t is in seconds.</span>
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