Answer:
The work furnished by the compressor is ![69.77kJ/s](https://tex.z-dn.net/?f=69.77kJ%2Fs)
The minimum work required for the state to change is ![55.26kW](https://tex.z-dn.net/?f=55.26kW)
Explanation:
The explanation to these solution is on the first, second , third and fourth uploaded image respectively
<u>I'm pretty sure your answer is B, because Sequential Control operates during order like a schedule</u>
Sequential Control=A control system in which the individual steps are processed in a predetermined order, progression from one sequence step to the next being dependent on defined conditions being satisfied.
Tell me if I'm incorrect but, Hope this helps!
Answer:
The value of critical length = 3.46 mm
The value of volume of fraction of fibers = 0.43
Explanation:
Given data
= 800 M pa
D = 0.017 mm
L = 2.3 mm
= 5500 M pa
= 18 M pa
= 13.5 M pa
(a) Critical fiber length is given by
![L_{c} = \sigma_{f} (\frac{D}{2 \sigma_{c} } )](https://tex.z-dn.net/?f=L_%7Bc%7D%20%3D%20%5Csigma_%7Bf%7D%20%28%5Cfrac%7BD%7D%7B2%20%5Csigma_%7Bc%7D%20%7D%20%29)
Put all the values in above equation we get
![L_{c} =5500 (\frac{0.017}{(2) (13.5)} )](https://tex.z-dn.net/?f=L_%7Bc%7D%20%3D5500%20%28%5Cfrac%7B0.017%7D%7B%282%29%20%2813.5%29%7D%20%29)
mm
This is the value of critical length.
(b).Since this critical length is greater than fiber length Than the volume fraction of fibers is given by
![V_{f} = \frac{\sigma_T - \sigma_m}{\frac{L\sigma_c}{D} - \sigma_m }](https://tex.z-dn.net/?f=V_%7Bf%7D%20%3D%20%5Cfrac%7B%5Csigma_T%20-%20%5Csigma_m%7D%7B%5Cfrac%7BL%5Csigma_c%7D%7BD%7D%20-%20%5Csigma_m%20%7D)
Put all the values in above formula we get
![V_{f} = \frac{800-18}{\frac{(2.3)(13.5)}{0.017} - 18 }](https://tex.z-dn.net/?f=V_%7Bf%7D%20%3D%20%5Cfrac%7B800-18%7D%7B%5Cfrac%7B%282.3%29%2813.5%29%7D%7B0.017%7D%20-%2018%20%7D)
= 0.43
This is the value of volume of fraction of fibers.