2 years ago

Which side of the disc sander do you sand on 1. Right 2. Left 3. Up 4. Down

1 answer:

3 0

$\mathbb \orange{Answer}$

$\mathbb \red{ Left}$

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makkiz [27]

Answer:

$\dot L_{steel} = 3.448\times 10^{-4}\,\frac{in}{min}$

Explanation:

The Young's module is:

$E = \frac{\sigma}{\frac{\Delta L}{L_{o}} }$

$E = \frac{\sigma\cdot L_{o}}{\dot L \cdot \Delta t}$

Let assume that both specimens have the same geometry and load rate. Then:

$E_{aluminium} \cdot \dot L_{aluminium} = E_{steel} \cdot \dot L_{steel}$

The displacement rate for steel is:

$\dot L_{steel} = \frac{E_{aluminium}}{E_{steel}}\cdot \dot L_{aluminium}$

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$\dot L_{steel} = 3.448\times 10^{-4}\,\frac{in}{min}$

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