The power supply converts the wall outlet AC power into DC power. T or F
1 answer:
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Answer:
The rate of heat transfer is - 935.392 kW
Explanation:
Given;
inlet pressure, P₁ = 20 bar
inlet temperature, T₁ = 440 k
outlet pressure, P₂ = 5 bar
outlet temperature, T₂ = 290 k
inlet velocity, v₁ = 18 m/s
outlet velocity, v₂ = 30 m/s
mass flow rate, Q = 6kg/s
developed power, W = 815 kW
From steam table;
at P₁ and T₁, interpolating between T = 400 and T = 450, h₁ = 3335.52 kJ/kg
at P₂ and T₂, interpolating between T= 250 and T= 300, h₂ = 3043.5 kJ/kg
Applying steady state energy balance equation;
substitute values above into this equation and evaluate the rate of heat transfer
Therefore, the rate of heat transfer, in kW, for a control volume enclosing the turbine is - 935.392 kW
Answer:
acceleration = 24.23 ms⁻¹
Explanation:
Let's gather the data:
The acceleration of the car is given by a = 0.5
The acceleration is the change in the speed in relation to time. In other words:
= a = a = 0.5
...1
Solving the differential equation yields:
v = 0.5 + C₁
Initial conditions : 0 = 0.5 + C₁
C₁ = -5
at any time t, the velocity is: v= 0.5- 5
Solving for distance, s = 0. 5 - 0.5 t - 0.5
18 = 0.5 - 0.5 t - 0.5
t = 3.71 s
Substitute t = 3.71 s
v= 0.5- 5
= 19.85 m/s
a = 0.5 ...1
= 20.3531
an =
=
= 13.1382
Magnitude of acceleration =
=
= 24.23 ms⁻¹ Ans