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ki77a [65]
2 years ago
5

Originally 21 acts were tentatively scheduled to perform at the arena; only 10 have been booked. What is the shortfall if the ot

her acts do not perform
Physics
1 answer:
Levart [38]2 years ago
5 0

Answer:

Here is the complete question.

Originally 21 acts were tentatively scheduled to perform at the arena; only 10 have been booked. What is the shortfall if the other acts do not perform, assuming an average profit margin of $175,000 for each concert?

The shortfall is of \$1925000

Explanation:

If all the acts were performed then the earnings would be 21\times 175,000=\$3,675,000

Now as mentioned in the question that only 10 have been performed so far.

Now the earning from these 10 acts =10\times 175,000=1,750,000

To find the shortfall.

We have to subtract the expected earnings with the actual earning from the concert.

So shortfall =(3,675,000-1,750,000)\$=\$1,925,000

So the shortfall is of \$1,925,000 if the other acts were not performed.

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Answer:

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let's reduce the revolutions to the SI system

      θ = 30.0 rev (2π rad / 1 rev) = 60π rad

let's calculate the angular velocity

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we clear from the first equation

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2 years ago
A 50.0-g Super Ball traveling at 25.0 m/s bounces off a brick wall and rebounds at 22.0 m/s. A
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Which descriptions best fit the labels? X: kinetic energy Y: potential energy X: potential energy Y: kinetic energy X: mechanica
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A man standing 1.54 m in front of a shaving mirror produces a real, inverted image 15.2 cm from it. What is the focal length of
zavuch27 [327]

Answer:

The focal length is 16.86 cm and the distance of the man  if he wants to form an upright image of his chin that is twice the chin's actual size is 8.43 cm.

Explanation:

Given that,

Object distance u=1.54 m =154 cm

Image distance v = 15.2 cm

Magnification = 2

We need to calculate the focal length

Using formula of mirror

\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}

Put the value into the formula

\dfrac{1}{f}=\dfrac{1}{15.2}+\dfrac{1}{-154}

\dfrac{1}{f}=\dfrac{347}{5852}

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We need to calculate the focal length

Using formula of magnification

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Put the value into the formula

2=\dfrac{v}{u}

v = -2u

Using formula of for focal length

\dfrac{1}{f}=\dfrac{1}{u}+\dfrac{1}{v}

\dfrac{1}{16.86}=\dfrac{1}{u}-\dfrac{1}{2u}

\dfrac{1}{16.86}=\dfrac{1}{2u}

2u=16.86

u=\dfrac{16.86}{2}

u=8.43\ cm

Hence, The focal length is 16.86 cm and the distance of the man  if he wants to form an upright image of his chin that is twice the chin's actual size is 8.43 cm.

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What is physical measurement? in Science​
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