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Olin [163]
3 years ago
11

Two similar waves X and Y travel through the same medium. Wave X has a frequency of 200 hertz and a

Physics
1 answer:
velikii [3]3 years ago
4 0

Answer:

The correct solution is option A "10 meters".

Explanation:

The given values are:

Wave X,

Frequency,

F_x=200 \ H_z

Wavelength

\lambda_x=35 \ m

Wave Y,

Frequency,

F_y=700 \ Hz

Let its wavelength = \lambda_y

As we know,

⇒  v=f \lambda

For both waves, medium is same then

⇒  v_x=v_y

⇒  f_x \lambda_x=f_y \lambda_y

then,

⇒  \lambda_y=\frac{f_x \lambda_x}{f_y}

On substituting the estimated values in the above equation, we get

⇒      =\frac{200\times 35}{700}

⇒      =\frac{7000}{700}

⇒      =10 \ m

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3 years ago
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A charge Q is uniformly spread over one surface of a very large nonconducting square elastic sheet having sides of length d. At
yaroslaw [1]

The electric field of a very large (essentially infinitely large) plane of charge is given by:

E = σ/(2ε₀)

E is the electric field, σ is the surface charge density, and ε₀ is the electric constant.

To determine σ:

σ = Q/A

Where Q is the total charge of the sheet and A is the sheet's area. The sheet is a square with a side length d, so A = d²:

σ = Q/d²

Make this substitution in the equation for E:

E = Q/(2ε₀d²)

We see that E is inversely proportional to the square of d:

E ∝ 1/d²

The electric field at P has some magnitude E. Now we double the side length of the sheet while keeping the same amount of charge Q distributed over the sheet. By the relationship of E with d, the electric field at P must now have a quarter of its original magnitude:

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4 0
3 years ago
Assuming there are no accidents or delays, the distance that a car travels down the interstate
Ganezh [65]

Explanation:

The distance that a car travels down the interstate  can be calculated with the following formula:

Distance = Speed x Time

(A) Speed of the car, v = 70 miles per hour = 31.29 m/s

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Distance = Speed x Time

D = 31.29 m/s × 21600 s

D = 675864 meters

or

D=6.75\times 10^5\ m

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D = 31.29 m/s × 54000 s

D = 1689660 meters

or

D=1.68\times 10^6\ m

Hence, this is the required solution.

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