$\bf log_{{ a}}(xy)\implies log_{{ a}}(x)+log_{{ a}}(y)
\\ \quad \\
% Logarithm of rationals
\\ \quad \\
% Logarithm of exponentials
log_{{ a}}\left( x^{{ b}} \right)\implies {{ b}}\cdot log_{{ a}}(x)\\\\
-----------------------------\\\\
log_b(xy^2z^{-6}\implies log_b(x)+log_b(y^2)+log_b(z^{-6})
\\\\\\log_b(x)+2log_b(y)-6log_b(z)$

now, the one below that, which is equivalent to that? well, just look above it

6 0

2 years ago

Factor -1/4 out of -1/2x -5/4y. (i will mark brainlyest)

mash [69]

Answer:

-1/4 (2x - 5y)

Step-by-step explanation:

For us to factor -1/4 out of -1/2x -5/4y

We will have to multiply the values in bracket by the reciprocal of -1/4 i.e -4 as shown

-1/2x - 5/4 y

= -1/4 (-4(-1/2x) - (-4)(-5/4y))

= -1/4 (4/2 x - 20/4 y)

= -1/4 (2x - 5y)

Hence the factored expression is -1/4 (2x - 5y)

5 0

2 years ago

What‘s 1+1? ;);) have a good day :)

galben [10]

Answer: 2 :))

Step-by-step explanation: hope you also have a good day!!

4 0

3 years ago

Read 2 more answers

2.3-7Given f(x)=x-3 and g(x)=x+2, find (f+g)(2).O A. -1O B. 9O C. 3O D. 5​

2.3-7Given f(x)=x-3 and g(x)=x+2, find (f+g)(2).O A. -1O B. 9O C. 3O D. 5