X²+y²+14x+2y+14=0
In order to solve this kind of problem, you will have to go back to te standard equation of the circle: (x-h)² + (y-k)² = R², where h and k are the coordinate of the center and R the radius
To find this equation you have to complete the square as shown below:
a) Assemble all x together as well as the y's : (x² + 14x) + (y² + 2y) + 14 = 0
b) complete the square of (x²+14x) it gives: (x+7)² - 49
c) complete the square of (y² 2y) it gives: (y+1)² - 1
<span>Rewrite the original equation:
</span>(x+7)² - 49 + (y+1)² - 1 +14 =0; Or (x+7)² + (y+1)² = -14 +1 + 49
Finally the original equation rewritten in the standard form is:
: (x+7)² + (y+1)² = 36. So the coordinates of the center O (-7, -1)
Answer:
44 magazines need to be sold
Step-by-step explanation:
Y=Mx+b
400=12x-124
524=12x
43.6667 or 43 (2/3)
round up since you cant sell 2/3 of a magazine
hope this helps! feel free to clarify if unsure
Answer: (7, 0)
Step-by-step explanation:
We have the system of equations:
9*x - y = 63
x = y + 7
We can see that the "x" is isolated in the second equation, then we can replace it in the first equation to get:
9*x - y = 63
9*(y + 7) - y = 63
Now we have an equation that only depends on one variable, so we can solve it:
9*y + 63 - y = 63
8*y + 63 = 63
8*y = 63 - 63 = 0
y = 0/8 = 0.
Now we know the value of y, we can replace this in one of the initial equations to find the value of x, i will replace this in the second equation:
x = y + 7 = 0 + 7 = 7
Then the point that is a solution for the system of equations is (7, 0)
