What would x be in this problem?

Mathematics

2 answers:

VARVARA [1.3K]2 years ago

7 0

Answer:1

Step-by-step explanation:

luda_lava [24]2 years ago

3 0

Answer:

$x=1$

Step-by-step explanation:

$6^5 = 6^x+6^4\\6^5 = 6^{x+4}\leftarrow \text {Apply product rule.}\\5=x+4 \leftarrow \text {Apply rule: If } a^{f(x)}=a^{g(x)}\text{, then} f(x) = g(x)\\5-4=x+4-4\\\boxed {x=1}$

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sergij07 [2.7K]

$f(t)=\begin{cases}0&\text{for }t$

Recall that

$u(t)=\begin{cases}0&\text{for }t$

Take it one piece at a time. For $t\ge0$ , we can scale $u(t)$ by -5:

$-5u(t)=\begin{cases}0&\text{for }t$

If we shift the argument by 1 and scale by -5, we have

$-5u(t-1)=\begin{cases}0&\text{for }t$

so if we subtract this from $-5u(t)$ , we'll end up with

$-5u(t)+5u(t-1)=\begin{cases}0&\text{for }t$

For the next piece, we can add another scaled and shifted step like

$-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

so that

$-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

For the last piece, we add one more term:

$6u(t-7)=\begin{cases}0&\text{for }t$

and so putting everything together, we get $f(t)$ :

$f(t)\equiv-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)+6u(t-7)$
$f(t)\equiv-5u(t)-u(t-1)+12u(t-7)$

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3 years ago

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Yuliya22 [10]

5(1/2) - 2 (1/4) =

11/2 - 9/4 =

22/4 - 9/4 =

13/4 or 3 (1/4)

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3 years ago

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Advocard [28]

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