Answer:
194,22g/mol
Explanation:
8*12,01+10*1,01+4*14,01+2*16=194,22g/mol
Answer:
5525 N/C
Explanation:
Magnitude of electric field ( E ) = 3500 N/c
Direction of electric field : positive X axis
point charge ( q ) = -9.0 * 10^-9
<u>Calculate the Magnitude of the net electric field at (a) x = -0.20 m</u>
Magnitude = 5525 N/C
Electric field due to q = ( 9 * 10^9 * 9 * 10^-9 ) / ( -0.2 )^2
= 81 / 0.04 = 2025 N/c
<em>Therefore the magnitude of the net electric field </em>
= 2025 + 3500
= 5525 N/C
That first one you have selected (3,-3) works in both equations so it's correct.
good job.
you can do this guess and test method with multiple choice answers. If it works in both equations it is the solution. Otherwise use substitution or elimination to combine the two into one equation in only one variable. Then you can solve for the one variable first and use it to solve for the other.
Answer:
Therefore energy is stored in the 1.0 mF capacitor is 5.56×10⁻⁹ J
Explanation:
Series capacitor: The ending point of a capacitor is the starting point of other capacitor.
If C₁ and C₂ are connected in series then the equivalent capacitance is C.
where 
Given that,
C₁ = 1.0 mF=1.0×10⁻³F and C₂ = 0.50mF=0.50×10⁻³F
If C is equivalent capacitance.
Then 
mF
Again given that the system is connected to a 100-v battery.
We know that
q=Cv
q= charge
C= capacitor
v= potential difference
Therefore
The electrical potential energy stored in a capacitor can be expressed
q= charge
c=capacitance of a capacitor
Therefore energy is stored in the 1.0 mF capacitor is
J
