The presence of potential energy between particles supports the shape of a heating curve.
<h2>Potential energy and heating curve</h2>
The existence of potential energy between particles supports the shape of a heating curve because potential energy causes the heating curve flat as well as in curve form. The heating curves show how the temperature changes as a substance is heated up.
The potential energy of the molecules will increase anytime energy is being supplied to the system but the temperature is not increasing so when the heating curve go flat it means there is potential energy so we can conclude that the existence of potential energy between particles supports the shape of a heating curve.
Learn more about heating curve here: brainly.com/question/11991469
Learn more: brainly.com/question/26153233
Answer:
The answers are options B,D and E
Explanation:
B) The particles in the liquid are slowly overcoming the forces of attraction and spreading out due to the thermal energy they are absorbing. This makes the liquid less dense as it slowly changes into a gas after reaching its boiling point.
D) The particles start absorbing the energy form the surroundings as latent heat of evaporation. They need this energy to overcome the strong forces of attraction between particles to change into the gaseous state
E) The particles have spaced out due to the thermal energy absorbed, making the liquid lighter and it rises upwards.
The answer to that probably would be C excuse me if I am wrong.
To solve this problem we will apply the concepts related to destructive interference from double-slit experiments. For this purpose we will define the path difference as,

Here,
= Wavelength
= Angle when occurs the interference point of destructive interference
Our values are given as,


Using the previous expression we have,





Therefore the distance between the two openings is 