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lukranit [14]
3 years ago
7

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Physics
1 answer:
balandron [24]3 years ago
6 0

Some examples you could look up on-line so I don't have to:

Speed of sound in sea water . . . 1,531 m/s

Speed of sound in iron . . . 5,130 m/s

Speed of sound in air . . . 340 m/s

This gives us

fastest . . . medium . . . slowest

<em>solid . . . . . liquid . . . . . gas</em>

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If wheel turning at a constant rate completes 100 revolutions in 10 s its angular speed is:
GenaCL600 [577]
The frequency of the wheel is given by:
f= \frac{N}{t}
where N is the number of revolutions and t is the time taken. By using N=100 and t=10 s, we find the frequency of the wheel:
f= \frac{100}{10 s}=10 s^{-1}

And now we can find the angular speed of the wheel, which is related to the frequency by:
\omega=2 \pi f=2 \pi (10 s^{-1})=62.8 s^{-1}
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4 years ago
Sound waves have the ability to cause objects to vibrate. If a paperback book is placed near a speaker and the volume of the spe
erik [133]

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yes with a lot of time it eventualy could be, but in short term no

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2 years ago
Which of the following would decrease the resistance to the flow of an electric current through a body?
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3 0
3 years ago
Read 2 more answers
I need assistance with this:​
emmainna [20.7K]

11: 75% = 0.75     12 / 0.75 = 16          The Knicks attempted 16 free throws.

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7 0
3 years ago
1. A piece of metal weighs 50.0 N in air, 36.0 N in water, and 41.0 N in an unknown
denis23 [38]

Answer:

a) 3.37 x 10^{3} kg/m^3

b) 6.42kg/m^{3}

Explanation:

a) Firstly we would calculate the volume of the metal using it`s weight in air and water , after finding the weight we would find the density .

Weight of metal in air = 50N = mg implies the mass of metal is 5kg.

Now the difference of weight of the metal in air and water = upthrust acting on it = volume (metal) p (liquid) g = V (1000)(10) = 14N. So volume of metal piece = 14 x 10^{-4}  kg/m^{3}. So density of metal = mass of metal / volume of metal = 5 / 14 x 10^{-4}  kg/m^{3} = 3.37 x 10^{3} kg/m^3

b) Water exerts a buoyant force to the metal which is 50−36 = 14N, which equals the weight of water displaced. The mass of water displaced is 14/10 = 1.4kg Since the density of water is 1kg/L, the volume displaced is 1.4L. Hence, we end up with 3.57kg/l. Moreover, the unknown liquid exerts a buoyant force of 9N. So the density of this liquid is 6.42kg/m^{3}

3 0
3 years ago
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