Answer:
197.76 m
Explanation:
r = Radius of the path = 20.6 km =
= The angle subtended by moon =
Distance traveled is given by
The distance traveled by the jet is 197.76 m
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Answer:
W = ½ m v²
Explanation:
In this exercise we must solve it in parts, in a first part we use the conservation of the moment to find the speed after the separation
We define the system formed by the two parts of the rocket, therefore the forces during internal separation and the moment are conserved
initial instant. before separation
p₀ = m v
final attempt. after separation
= m /2 0 + m /2 v_{f}
p₀ = p_{f}
m v = m /2
v_{f}= 2 v
this is the speed of the second part of the ship
now we can use the relation of work and energy, which establishes that the work is initial to the variation of the kinetic energy of the body
initial energy
K₀ = ½ m v²
final energy
= ½ m/2 0 + ½ m/2 v_{f}²
K_{f} = ¼ m (2v)²
K_{f} = m v²
the expression for work is
W = ΔK = K_{f} - K₀
W = m v² - ½ m v²
W = ½ m v²
To solve this problem we will apply the concepts related to the Area, the power and the proportionality relationships between intensity and distance.
The expression for sound power is,
Here,
A = Area
I = Intensity
P = Power
At the same time the area can be written as,
Now the intensity is inversely proportional to the square of the distance from the source, then
The expression for the intensity at different distance is
Here,
= Intensity at distance 1
= Intensity at distance 2
= Distance 1 from light source
= Distance 2 from the light source
If we rearrange the expression to find the intensity at second position we have,
If we replace with our values at this equation we have,
Now using the equation to find the area we have that
Finally with the intensity and the area we can find the sound power, which is
Power is defined as the quantity of Energy per second, then