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ehidna [41]
3 years ago
9

The work-energy theorem states that a force acting on a particle as it moves over a ______ changes the ______ energy of the part

icle if the force has a component parallel to the motion.
Choose the best answer to fill in the blanks above:

distance / potential
distance / kinetic
vertical displacement / potential
none of the above
Physics
1 answer:
ololo11 [35]3 years ago
6 0

Answer:

distance/ kinetic

Explanation:

According to the work energy theorem, the work done by all forces is equal to the change in kinetic energy of the body.

So, As the force is applied in the same direction of the distance traveled,so only the kinetic energy of the body changes as after application of force, the speed of the body changes.

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In a local bar, a customer slides an empty beer mug down the counter for a refill. The height of the counter is 1.46 m. The mug
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Answer:

(a). The horizontal velocity is 1.46 m/s.

(b). The direction of the mug's velocity just before it hit the floor is 74.7° below the horizontal.

Explanation:

Given that,

Height of the counter = 1.46 m

Distance = 0.80 m

We need to calculate the time

Using equation of motion

s_{y}=ut+\dfrac{1}{2}gt^2

s_{y}=\dfrac{1}{2}gt^2

Put the value into the formula

1.46=\dfrac{1}{2}\times9.8\times t^2

t^2=\dfrac{1.46\times 2}{9.8}

t=\sqrt{\dfrac{1.46\times2}{9.8}}

t=0.545\ sec

Here, horizontal velocity is constant

(a). We need to calculate the velocity

Using formula of velocity

v_{x}=\dfrac{d}{t}

Put the value into the formula

v_{x}=\dfrac{0.80}{0.545}

v_{x}=1.46\ m/s

(b). We need to calculate the final velocity

Using equation of motion

v_{f}^2=u^2+2as

Put the value into the formula

v_{f}^2=0+2\times9.8\times1.46

v_{f}=\sqrt{28.616}

v_{f}=5.34\ m/s

The velocity is 5.34 m/s downward.

We need to calculate the direction

Using formula of direction

\tan\theta=\dfrac{v_{y}}{v_{x}}

\theta=\tan^{-1}(\dfrac{5.34}{1.46})

\theta=74.7^{\circ}

Hence, (a). The horizontal velocity is 1.46 m/s.

(b). The direction of the mug's velocity just before it hit the floor is 74.7° below the horizontal.

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4 years ago
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