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2 years ago

5

If "38 %" of the light passes through this combination of filters, what is the angle between the transmission axes of the filter

s

1 answer:

qaws [65]2 years ago

4 0

Answer:

<em>52°</em>

Explanation:

The initial intensity $I_{0}$ = $I$

The final intensity $I_{f}$ = 38% of $I$ = 0.38

From the polarizing equation

$I_{f} = I_{0} cos^{2}$ θ

substituting values, we have

$0.38I = I cos^{2}$ θ

0.38 = $cos^2$ θ

cosθ = $\sqrt{0.38}$

cosθ = 0.6164

θ = $cos^{-1}$ 0.6164

θ = 51.9 ≅ <em>52°</em>

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The movement of particles from high to low concentration. True or False

Digiron [165]

Question:

Diffusion is the movement of particles from high to low concentration. True or False

Answer:

True.

Explanation:

Diffusion is a process that allows the movement of substance or particles in and out of cells through a semipermeable membrane.

Diffusion is a process that allows the spread or movement of particles from the region of higher concentration to a region of lower concentration through a semipermeable membrane.

Diffusion only occurs in gases and solution but not in solids, it also occurs only where particles can move freely.

Note: When particles move from the region of higher concentration to a lower concentration, it gives room for even, uniform and random distribution of particles.

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2 years ago

Figure 23.9 shows a sliding mass on a spring. Assume there is no friction.

Tom [10]

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2 years ago

Need help with physics please

bazaltina [42]

The centripetal force : F = 293.3125 N

<h3>Further explanation</h3>

Given

mass = 65 kg

v = 9.5 m/s

r = 20 m

Required

the centripetal force

Solution

Centripetal force is a force acting on objects that move in a circle in the direction toward the center of the circle

$\large {\boxed {\bold {F = \frac {mv ^ 2} {R}}}$

F = centripetal force, N

m = mass, Kg

v = linear velocity, m / s

r = radius, m

Input the value :

F = 65 x 9.5² / 20

F = 293.3125 N

4 0

2 years ago

How fast can the 140 a current through a 0.200 h inductor be shut off if the induced emf cannot exceed 80.0 v?

Vesna [10]

Recall that to compute for the emf of a circuit given current and inductance, we must recall that

$emf = - M \frac{\Delta I }{\Delta t}$

where I is the current (A), M is the mutual inductance (h), and t is the time (ms). Since the current must not exceed 80.0 V, we have

$80.0 \geq 0.200(\frac{140}{t})$
$t \geq \frac{28.0}{80}$
$t \geq 0.35$

From this, we see that it must take at least 0.35 ms so it doesn't exceed 80 V.
Answer: 0.35 ms

7 0

2 years ago

A bubble, located 0.200 m beneath the surface in a glass of beer, rises to the top. The air pressure at the top is 1.01 ???? 10

SIZIF [17.4K]

Answer:

the ratio of the bubble’s volume at the top to its volume at the bottom is 1.019

Explanation:

given information

h = 0.2 m

$P_{0}$ = 1.01 x $10^{5}$ Pa

$P_{1} V_{1} = P_{2} V_{2}$

$\frac{V_{2} }{V_{1}} = \frac{P_{1} }{P_{2}}$

$P_{1}$ = $P_{0}$ + ρgh, ρ = 1000 kg/ $m^{3}$

$P_{1}$ = 1.01 x $10^{5}$ Pa + (1000 x 9.8 x 0.2) = 1,0296 x $10^{5}$ Pa

$P_{2}$ = $P_{0}$ = $10^{5}$ Pa

thus,

$\frac{V_{2} }{V_{1}} = 1,0296 x [tex]10^{5}$ / $10^{5}$ = 1.019

8 0

3 years ago