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kumpel [21]
3 years ago
5

If "38 %" of the light passes through this combination of filters, what is the angle between the transmission axes of the filter

s
Physics
1 answer:
qaws [65]3 years ago
4 0

Answer:

<em>52°</em>

Explanation:

The initial intensity I_{0} = I

The final intensity I_{f} = 38% of I = 0.38

From the polarizing equation

I_{f} = I_{0} cos^{2}θ

substituting values, we have

0.38I = I cos^{2}θ

0.38 = cos^2θ

cosθ = \sqrt{0.38}

cosθ = 0.6164

θ = cos^{-1} 0.6164

θ = 51.9 ≅ <em>52°</em>

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A motorcycle, which has an initial linear speed of 9.8 m/s, decelerates to a speed of 2.2 m/s in 3.4 s. Each wheel has a radius
miss Akunina [59]

Answer:

The angular acceleration and angular displacement is -2.24\ m/s^2 and 31.34 rad .

Explanation:

Given :

Initial linear speed , u = 9.8 m/s .

Final speed , v = 2.2 m/s .

Time taken , t = 3.4 s .

Radius of wheel , r = 0.65 m .

So , decelerates of wheel is given by :

v-u=at\\2.2-9.8=a\times 3.4\\a=-2.24\ m/s^2

Therefore , angular velocity is given by :

\omega=\dfrac{a}{r}\\\\\omega=\dfrac{-2.24}{0.65}\\\\\omega =-3.45\ rad/s^2

Now , linear displacement is :

s=ut+\dfrac{at^2}{2}\\\\s=9.8\times 3.4+\dfrac{-2.24\times 3.4^2}{2}\\\\s=20.37\ m

Therefore , angular displacement is :

d=\dfrac{s}{r}\\\\d=\dfrac{20.37}{0.65}\\\\d=31.34\ rad

Hence , this is the required solution .

4 0
3 years ago
In electroplating, the object to be plated is which part of an electrolytic cell? cathode or anode
Bingel [31]

Since the anode dissolves and goes to the cathode. The object to be electroplated is kept at the cathode.

Please mark me as brainliest.

7 0
3 years ago
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Vestobular receptors enable one to balance. <br><br> True or False
frozen [14]
The answer is actually true. i just took the test and i put false and it was wrong
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2 years ago
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What is the potential difference across lamp 1
Alex73 [517]

Answer:

1+1=2

Explanation:

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7 0
2 years ago
What is the acceleration along the ground of a 10 kg wagon when it is pulled with a force of 44 N at an angle of 35° above the
Olegator [25]

The acceleration of the wagon along the ground is 3.6 m/s².

To solve the problem above, we need to use the formula of acceleration as related to force and mass.

Acceleration: This can be defined as the rate of change of velocity.

⇒ Formula:

  • Fcos∅ = ma................. Equation 1

⇒ Where:

  • F = Force
  • ∅ = angle above the horizontal
  • m = mass of the wagon
  • a = acceleration of the wagon

⇒ make a the subject of equation 1

  • a = Fcos∅/m..................... Equation 2

From the question,

⇒ Given:

  • F = 44 N
  • ∅ = 35°
  • m = 10 kg

⇒ Substitute these values into equation 2

  • a = 44(cos35°)/10
  • a = 44(0.8191)/10
  • a = 3.6 m/s²

Hence, The acceleration of the wagon along the ground is 3.6 m/s²

Learn more about acceleration here: brainly.com/question/9408577

3 0
2 years ago
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