1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kumpel [21]
3 years ago
5

If "38 %" of the light passes through this combination of filters, what is the angle between the transmission axes of the filter

s
Physics
1 answer:
qaws [65]3 years ago
4 0

Answer:

<em>52°</em>

Explanation:

The initial intensity I_{0} = I

The final intensity I_{f} = 38% of I = 0.38

From the polarizing equation

I_{f} = I_{0} cos^{2}θ

substituting values, we have

0.38I = I cos^{2}θ

0.38 = cos^2θ

cosθ = \sqrt{0.38}

cosθ = 0.6164

θ = cos^{-1} 0.6164

θ = 51.9 ≅ <em>52°</em>

You might be interested in
Positive Charge Q is distributed uniformly along the x-axis from x=0 to x=a. A positive point charge q is located on the positiv
deff fn [24]

Answer:

 electric field E = - k Q (1 /r(r-a)), force    F = - k Q qo / r (r-a) and force for r>>a    F ≈ - k Q qo / r²

Explanation:

You are asked to find the electric field of a continuous charge distribution, so we must use the equation

       

           E = k ∫dp /r²

Where k is the Coulomb constant that is worth 8.99 10⁹ N m² / C², r is the distance between the load distribution and the test charge, in this case everything is on the X axis.

We must find the charge differential (dq), let's use that uniformly distributed and create a linear charge density

          λ = q / x

As it is constant, we can write it based on differentials

         λ = dq / dx

         dq = λ dx

We already have all the terms, let's  integrate enter its limits, lower the distance from the left end of the distribution to the test charge (x = r) and the upper limit that is the distance from the left end of distribution to the test load ( x = r - a) where r> a

         E = k ∫ λ dx / x²

         E = k la (- 1 / x)

Let's get the negative sign from the parentheses

         E = - k λ (1 / x)

         E = - k λ (1 /(r-a)  -1 /r) = - k λ [a / r (r-a)]

Let's change the charge density with the value of the total charge λ = Q / a

         E = - k Q/a  [a / r (r-a)]

         E = - k Q (1 /r(r-a))

b) We calculate the force.  

         F = E qo

         F = - k Q qo / r (r-a)

c) the force for charge porbe very far r >> a. In this case we can take r from the parentheses and neglect (a/r)

         F = - k Qqo / r² (1 -  a/r)

         F ≈ - k Q qo / r²

6 0
3 years ago
Earth's dynamic processes allow our plant to recycle:
kvasek [131]
Earth's dynamic processes allow our planet to recycle air, surface materials, and water. The correct answer is D.
8 0
3 years ago
Read 2 more answers
If i hold a glass full of air upside down, and i take it to the bottom of the swimming pool without tipping it, the density (thi
s2008m [1.1K]
The answer to fill in the blank in the question above is "greater than" based on the physic of the air density. The density of air is affected by the temperature and the pressure based on the ideal gas law. A high pressure will make the air becomes denser and the bottom of swimming pool has a higher pressure than the surface<span>.</span>
6 0
3 years ago
QUESTION 3
Alisiya [41]

The force of frictions is opposed to relative motion.

The acceleration of the crate is approximately <u>2.937 m/s²</u>.

Reason:

The given parameters are;

The mass of the wood, m = 100 kg

The force which can move the wood, F = 588 N

Wood on wood static friction, \mu_s = 0.5

Wood on wood kinetic friction, \mu_k = 0.3

Solution;

The force of friction, F_f, acting when the crate is moving is given as

follows;

F_f = m × g × \mu_k

Where;

g = The acceleration due to gravity ≈ 9.81 m/s²

Therefore, we have;

F_f = 100 × 9.81 × 0.3 = 294.3

The force of friction, F_f = 294.3 N

The force with which the crate moves, F = 588 - 294.3 = 293.7

The force with which the crate moves, F = 293.7 N

Force = Mass, m × Acceleration, a

a = \dfrac{F}{m}

Therefore;

a = \dfrac{293.7 \ N}{100 \ kg} = 2.937

The acceleration of the crate, a ≈ <u>2.937 m/s²</u>.

Learn more about friction here:

brainly.com/question/94428

8 0
2 years ago
Find the westward component of a resultant vector 85.42 unit, 23 degrees W of N
Sindrei [870]

Since the angle is West of North, therefore to find for the westward component (horizontal component) of the vector, we use the sin function:

sin θ = opposite side / hypotenuse = westward component / resultant vector

So the westward component (x) is:

x = 85.42 sin 23

<span>x = 33.38 unit</span>

5 0
3 years ago
Other questions:
  • Bill and Amy want to ride their bikes from their neighborhood to school which is 14.4 kilometers
    8·1 answer
  • Two football players with mass 75 kg and 100 kg run directly toward each other with speeds of 6 m/s and 8 m/s respectively. if t
    15·1 answer
  • Uranus has an orbital period of 84.07 years. In two or more complete sentences, explain how to calculate the average distance fr
    15·2 answers
  • If the motor exerts a constant force of 300 N on the cable, determine the speed of the 26-kg crate when it travels s = 10 m up t
    10·1 answer
  • In what way has technology used aboard the International Space Station benefitted humans back on Earth?
    9·2 answers
  • Determine the power that needs to besupplied by the fanifthe desired velocity is 0.05 m3/s and the cross-sectional area is 20 cm
    6·1 answer
  • So long as there are(is) ______ there is no movement.
    15·1 answer
  • Describe how noise-cancelling headphones modify the sound waves around the user. Your answer should be three to four sentences i
    13·1 answer
  • Which variables are involved in understanding Kepler's third law of motion? (1 point)
    13·2 answers
  • Rearrange the equation = KE<br> -1<br> 2<br> - my? to solve for v. Show your work.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!