Answer:
Given that
V2/V1= 0.25
And we know that in adiabatic process
TV^န-1= constant
So
T1/T2=( V1 /V2)^ န-1
So = ( 1/0.25)^ 0.66= 2.5
Also PV^န= constant
So P1/P2= (V2/V1)^န
= (1/0.25)^1.66 = 9.98
A. RMS speed is
Vrms= √ 3RT/M
But this is also
Vrms 2/Vrms1= (√T2/T1)
Vrms2=√2.5= 1.6vrms1
B.
Lambda=V/4π√2πr²N
So
Lambda 2/lambda 1= V2/V1 = 0.25
So the mean free path can be inferred to be 0.25 times the first mean free path
C. Using
Eth= 3/2KT
So Eth2/Eth1= T2/T1
So
Eth2= 2.5Eth1
D.
Using CV= 3/2R
Cvf= Cvi
So molar specific heat constant does not change
Answer:
not work.
Explanation:
if u are saying in a series circuit...
if 1 build burns out and theres other bulbs the circuit wont work anymore.
Dispersion im pretty sure
Answer:
Height h = 37.8 m
Explanation:
Given
:
Velocity of car (v) = 98 km / h
Acceleration of gravity = 9.8 m/s²
Computation:
Acceleration of gravity = 9.8 m/s²
Acceleration of gravity = (98)(1,000 m / 3,600 s)
Acceleration of gravity = 27.22 m/s
By using law of conservation of energy
;
(1/2)mv² = mgh
h = v² / 2g
h = 27.22² / 2(9.8)
Height h = 37.8 m
Answer:
The manipulated variable is also known as the independent variable
Explanation:
When remembering this remember independent as in you independently change the outcome
