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Karolina [17]
3 years ago
11

Stacy uses a spinner with six equal sections numbered 2, 2, 3, 4, 5, and 6 to play a game. Stacy spins the pointer 120 times and

records the results. The pointer lands 30 times on a section numbered 2, 19 times on 3, 25 times on 4, 29 times on 5, and 17 times on 6. How does the theoretical probability compare with the experimental probability of landing on an even number? Use the drop-down menus to explain your answer.
The probability is greater than the probability of landing on an even number. The probability is 72120 and the probability is 80120.
Mathematics
1 answer:
ivann1987 [24]3 years ago
5 0

Answer:

Even numbers are 2,4,6 for this case and the experimental probability of being even is given by:

p = \frac{30+25+17}{120}= \frac{72}{120}= 0.6

Now we can find the theorical probability since we have 6 possible outcomes 2, 2, 3, 4, 5, and 6 we have 4 even numbers in the sample space and the theorical probability is given by:

p= \frac{4}{6}= 0.667

Then we can conclude that the empirical probability is lower than the theorical probability (0.6<0.667)  for this experiment

Step-by-step explanation:

For this case we wan find the probability associated to the experiment we know that. The pointer lands 30 times on a section numbered 2, 19 times on 3, 25 times on 4, 29 times on 5, and 17 times on 6.

Even numbers are 2,4,6 for this case and the experimental probability of being even is given by:

p = \frac{30+25+17}{120}= \frac{72}{120}= 0.6

Now we can find the theorical probability since we have 6 possible outcomes 2, 2, 3, 4, 5, and 6 we have 4 even numbers in the sample space and the theorical probability is given by:

p= \frac{4}{6}= 0.667

Then we can conclude that the empirical probability is lower than the theorical probability (0.6<0.667)  for this experiment

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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3 0
3 years ago
There are 5000 undergraduates registered at a certain college. Of them, 448 are taking one course, are taking two courses, 675 a
olga55 [171]

Answer:

Step-by-step explanation:

Hello!

There are some values missing, so I'll find the probability distribution using others as example. Afterwards you can calculate the ones corresponding to this exercise following the same steps.

Considering there are 5000 undergraduates registered in the college.

465 are taking one course

658 are taking two courses

566 are taking three courses

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1344 are taking five courses

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First you have to define the variable of interest. To identify it you have to ask yourself the following question: what is the characteristic of this population that is being measured?

The answer is "the number of courses an undergraduate is taking" and this will be the study variable X

X can take values from 1 to 6 courses.

To calculate the probability of each value of X, you have to divide the "number of students taking Xi courses" by "total number of students registered in the college"

For

X=1

P(1)= 465/5000= 0.093

X=2

P(2)= 658/5000= 0.1316

X=3

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X=4

P(4)= 1877/5000= 0.3754

X=5

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X=6

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For this to be a probability distribution the following condition should be met:

F(X)= ∑P(X) = 1

In this example: 0.093 + 0.1316 + 0.1132 + 0.3754 + 0.2688 + 0.018 = 1

I hope this helps!

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3 years ago
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Slav-nsk [51]

Answer:

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5.96-3.82= 2.14

So, your answer would be 2.14

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