some important molecules are too large to pass through the cell membrane.
Hope this helps!
-Payshence
<h3><u>Answer;</u></h3>
Label A; Mitochondria.
Label B; Nucleus.
Label C; Golgi apparatus.
Label D; Rough endoplasmic reticulum
<h3><u>Explanation;</u></h3>
- All the above are various organelles in a eukaryotic cells each carrying different cellular activity to enhance the functioning of a cell.
Label A; Mitochondria.
- <u>Mitochondria</u> is the powerhouse of the cell which converts glucose to energy rich molecules of ATP, through the process of cellular respiration.
Label B; Nucleus.
- <u>Nucleus</u> contains the genetic material or DNA, RNA , nucleolus, chromatin fibres and proteins. It contains the chromosomes which control the hereditary characteristics.It also regulates all the activities of the cell.
Label C; Golgi apparatus.
- <u>Golgi apparatus;</u> they are also called Golgi bodies. They function in modifying, sorting and packaging of proteins for secretion. They are also involved in the transport of lipids around the cell, and the creation of lysosomes.
Label D; Rough endoplasmic reticulum
- <u>The rough endoplasmic reticulum</u> provides surface for protein synthesis. It is also used to transport cellular contents from one cell to another.
- The risbosomes attached on the rough endoplasmic reticulum are resposible for the protein synthesis through the process of translation.
Answer: The taproot
Explanation: A deep taproot helps plants use moisture held in deeper soil layers, and they can have great drought resistance compared to fibrous-rooted plants. An example is honey mesquite (Prosopis juliflora), which is known to send its roots down 150 feet to get water.
Answer:
25%
Explanation:
<em>The approximate proportion of G + C content in the genome of E. coli has been reported to be 50%. According to Chargaff's rule, the amount of guanine in any DNA must be approximately equal to the amount of cytosine. </em>Hence,
if G + C = 50 and G = C,
then
G = C = 25
Therefore, the approximate percentage of guanine in the genome of <em>E. coli </em>would be 25.
