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GenaCL600 [577]
2 years ago
7

What is the proper formula for vanadium (iv) percholrate?

Chemistry
1 answer:
VLD [36.1K]2 years ago
6 0

Answer:VO(ClO4)3 i'm sure this is it

Explanation:

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How many gram-atoms are in 120-gram sample of calcium metal? How many atoms is this?
Elden [556K]
(sample g/1) X (1 mole/40.078(MW of Ca)) = moles of sample (moles of sample)(6.022 x 10^23( no of atoms)/ 1 mole) = # of atoms in a 120 g sample of calcium Avogadro's number=6.022x 10^23 atoms in 1 mole
3 0
3 years ago
Some animals that live in extremely cold environments protect themselves from freezing by increasing the molality of certain che
lara [203]
  • Molality is defined as the number of moles of solute dissolved per 1000g(1kg) of solvent.
  • It is represented by m

\\ \sf \longmapsto m=\dfrac{Moles\:of\:solute}{Wt\:of\:solvent(in\:g)}\times 1000

8 0
3 years ago
a particular application calls for N2 g with a density of 1.80 g/L at 32 degrees C what must be the pressure of the n2 g in mill
baherus [9]

Answer:

1223.38 mmHg

Explanation:

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 62.3637\text{ L.mmHg }mol^{-1}K^{-1}

Also,  

Moles = mass (m) / Molar mass (M)

Density (d)  = Mass (m) / Volume (V)

So, the ideal gas equation can be written as:

PM=dRT

Given that:-

d = 1.80 g/L

Temperature = 32 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (32 + 273.15) K = 305.15 K

Molar mass of nitrogen gas = 28 g/mol

Applying the equation as:

P × 28 g/mol  = 1.80 g/L × 62.3637 L.mmHg/K.mol × 305.15 K

⇒P = 1223.38 mmHg

<u>1223.38 mmHg must be the pressure of the nitrogen gas.</u>

5 0
3 years ago
The melting point of table salt is 801 degrees celsius. is this a physical or chemical property?
Valentin [98]
It is a Physical property because like water it changes into a ice cube but it can be melted into water or be turned back into an ice cube.
5 0
2 years ago
An average bushel of apples has a mass of 10 kg and contains 5 dozen apples.
Alina [70]

Answer:

Average mass of 6 apple  = 1 kg

Explanation:

Given:

Average mass of 5 dozen apple = 10 kg

Find:

Average mass of 6 apple

Computation:

Average mass of 6 apple  = [Average mass of 1 apple] x [6 apple]

Average mass of 6 apple  = [10/(12 x 5)] x [6]

Average mass of 6 apple  = 1 kg

3 0
2 years ago
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