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7nadin3 [17]
3 years ago
11

If you are eating a hamburger, it is an example of a consumer eating another consumer.

Chemistry
1 answer:
Step2247 [10]3 years ago
5 0
True is the answer.....
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PLZ HELP I WILL GIVE BRAINLY AND 50 POINTS
Oxana [17]

Answer:

1.  State problem

2. Form hypothesis

3.  Conduct experiment

4.  Interpret data

5.  Draw conclusion

Explanation:

4 0
3 years ago
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K + Cl2 -&gt; KCI <br> Balance equation
PtichkaEL [24]

Answer:

2K + Cl2 -> 2KCl

Explanation:

Just balancing :3

7 0
3 years ago
How many moles of potassium are contained in 150 g of potassium
BaLLatris [955]

Answer:

150 g of potassium contained 3.8 moles of potassium.

Explanation:

Given data:

Mass of potassium = 150 g

Moles of potassium = ?

Solution:

Number of moles = mass/ molar mass

Molar mass of potassium = 39 g/mol

Now we will put the values in formula:

Number of moles = mass/ molar mass

Number of moles = 150 g/ 39 g/mol

Number of moles = 3.8 mol

150 g of potassium contained 3.8 moles of potassium.

3 0
4 years ago
The volume of a gas held at constant temperature varies indirectly as the pressure of the gas. If the volume of a gas is 1200 cu
kvasek [131]

Answer:

Volume of the gas at 500 mm Hg pressure is 960 cm^{3}

Explanation:

Let's assume the gas behaves ideally.

According to combined gas law for an ideal gas-

                  \frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}

Where P_{1} and  P_{2} are initial and final pressure of the gas respectively.  V_{1} and  V_{2} are initial and final volume of the gas respectively.  T_{1} and  T_{2} are initial and final temperature of the gas in kelvin respectively.

Here T_{1} = T_{2}, V_{1} = 1200 cm^{3}, P_{1} = 400 mm Hg, P_{2} = 500 mm Hg

So, V_{2}=\frac{P_{1}V_{1}T_{2}}{T_{1}P_{2}}

Hence V_{2}=\frac{400\times 1200}{500}[tex]cm^{3}=960 cm^{3}[/tex]

Hence volume of the gas at 500 mm Hg pressure is 960 cm^{3}

3 0
4 years ago
What is the oxidation state of nitrogen in N ?
g100num [7]

Answer:

+5

Explanation:

4 0
3 years ago
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