All categories

3 years ago

Original price: ? Discount: 30% sale price: 206.50

Mathematics

2 answers:

viktelen [127]3 years ago

7 0

30%*206.50= 61.95
206.50+61.95=268.45
Original Price: $268.45

Lyrx [107]3 years ago

5 0

11.875 thats your answer

You might be interested in

The selling price of the Robertsons family house dropped from $500,000 to $250,000. What was the percent decrease in the value o

Alexus [3.1K]

Answer:

50%

Step-by-step explanation:

You can literally do it mentally lol

$500,000

- $250,000

$250,000

so by common sense, it's 50%

Hope it helped!

5 0

2 years ago

Read 2 more answers

True or False:

DIA [1.3K]

True. If you're just changing the form, yes. But remember when you change one side of an equation, you must change the other in the same way.

7 0

3 years ago

Read 2 more answers

There are 8 sophomores on the academic team. At the last competition, they each took the math test. Their scores were 82%, 92%,

Sav [38]

Answer:

79%

Step-by-step explanation:

To find the median, you need to arrange the numbers in ascending order. Than pick the middle number. If there are two middle numbers then you add them together and then divide by 2.

3 0

3 years ago

Samples of skin experiencing desquamation are analyzed for both moisture and melanin content. The results from 100 skin samples

zheka24 [161]

Answer: a. 0.40 b. 0.23 c . 0.435 d . 0.25

Step-by-step explanation:

melanin content Total

high low

moisture high 13 10 23

content low 47 30 77

Total 60 40 100

Let A denote the event that a sample has low melanin content, and let B denote the event that a sample has high moisture content.

a) Total skin samples has low melanin content = 10+30=40

P(A)= $\dfrac{40}{100}=0.40$

b) Total skin samples has high moisture content = 13+10=23

P(B) = $\dfrac{23}{100}=0.23$

c) A ∩ B = Total skin samples has both low melanin content and high moisture content =10

P(A ∩ B) = $\dfrac{10}{100}=0.10$

Using conditional probability formula , $P (A|B)=\dfrac{P(A\cap B)}{P(B)}$

$P (A|B)=\dfrac{0.10}{0.23}=0.434782608696\approx0.435$

d) $P (B|A)=\dfrac{P(A\cap B)}{P(A)}$

$P (B|A)=\dfrac{0.10}{0.40}=0.25$

8 0

3 years ago

What’s the solution for x-0= 0

Dominik [7]

I’m pretty sure it’s 0

7 0

3 years ago