Answer:
1. b ∈ B 2. ∀ a ∈ N; 2a ∈ Z 3. N ⊂ Z ⊂ Q ⊂ R 4. J ≤ J⁻¹ : J ∈ Z⁻
Step-by-step explanation:
1. Let b be the number and B be the set, so mathematically, it is written as
b ∈ B.
2. Let a be an element of natural number N and 2a be an even number. Since 2a is in the set of integers Z, we write
∀ a ∈ N; 2a ∈ Z
3. Let N represent the set of natural numbers, Z represent the set of integers, Q represent the set of rational numbers, and R represent the set of rational numbers.
Since each set is a subset of the latter set, we write
N ⊂ Z ⊂ Q ⊂ R .
4. Let J be the negative integer which is an element if negative integers. Let the set of negative integers be represented by Z⁻. Since J is less than or equal to its inverse, we write
J ≤ J⁻¹ : J ∈ Z⁻
I would say about 40 kilometers it’s ifs 20 around her neighborhood that 20+20=40 and walking tha rest made the question easier but yea 40
Subtract negative = add
88 + 35 = 123
The solution is 123
Answer:
a line labeled g of x that passes through points negative 1, negative 2 and 0, 2
Step-by-step explanation:
we have
To determine g(x), substitute the variable x by (x+1) in the function f(x)
so
therefore
a line labeled g of x that passes through points negative 1, negative 2 and 0, 2
